我有以下价值
public class Identification : IEquatable<Identification>
{
public int Id { get; set; }
public byte[] FileContent { get; set; }
public int ProjectId { get; set; }
}
我使用resharper生成了平等成员
public bool Equals(Identification other)
{
if (ReferenceEquals(null, other)) return false;
if (ReferenceEquals(this, other)) return true;
return Id == other.Id && Equals(FileContent, other.FileContent) && ProjectId == other.ProjectId;
}
public override bool Equals(object obj)
{
if (ReferenceEquals(null, obj)) return false;
if (ReferenceEquals(this, obj)) return true;
if (obj.GetType() != this.GetType()) return false;
return Equals((Identification) obj);
}
public override int GetHashCode()
{
unchecked
{
var hashCode = Id;
hashCode = (hashCode*397) ^ (FileContent != null ? FileContent.GetHashCode() : 0);
hashCode = (hashCode*397) ^ ProjectId;
return hashCode;
}
}
public static bool operator ==(Identification left, Identification right)
{
return Equals(left, right);
}
public static bool operator !=(Identification left, Identification right)
{
return !Equals(left, right);
}
但是当我想要从存储库返回之前和之后进行单元测试时,它会失败。尽管在失败消息中具有完全相同的属性。
var identification = fixture
.Build<Identification>()
.With(x => x.ProjectId, projet.Id)
.Create();
await repository.CreateIdentification(identification);
var returned = await repository.GetIdentification(identification.Id);
Assert.Equal()失败
预期:标识{FileContent = [56,192,243],Id = 8,ProjectId = 42}
实际:标识{FileContent = [56,192,243],Id = 8,ProjectId = 42}
如果重要的话,我正在使用Npgsql和Dapper。
答案 0 :(得分:1)
对于检查:
的数组,您应该使用Enumerable.SequenceEqual
null
,或者两个数组都不是null
。Length
。像这样的东西
public bool Equals(Identification other)
{
if (ReferenceEquals(null, other))
return false;
else if (ReferenceEquals(this, other))
return true;
return Id == other.Id &&
ProjectId == other.ProjectId &&
Enumerable.SequenceEqual(FileContent, other.FileContent);
}
由于Enumerable.SequenceEqual
很可能耗费时间,我已将其转移到比较的末尾(如果ProjectId
未能相等,则无需检查数组)