我是mysql的新手所以我试图为我的工作制定付款时间表。我需要将总数显示为"付款"。
<?php
$sql = "SELECT id, DATE_FORMAT(datum, '%d/%m/%Y'), tijd, uren, floor(uren*loon) as payment FROM uren_gewerkt";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr><th>Datum</th><th>Tijden</th><th>Uren</th><th>Loon</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["DATE_FORMAT(datum, '%d/%m/%Y')"]."</td><td>".$row["tijd"]."</td><td>".$row["uren"]."</td><td>€".$row["payment"]."</td></tr>";
}
echo "</table>";
echo "Totaal:"; //Sum of payment goes here
}
else {
echo "0 results";
}
?>
注意&#34; Loon&#34; (从楼层(uren * loon)是固定数字(9.56)
答案 0 :(得分:1)
SELECT SUM(floor(uren*loon)) as total FROM uren_gewerkt
或者在PHP中执行:
$total = 0;
//here goes your while loop
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["DATE_FORMAT(datum, '%d/%m/%Y')"]."</td><td>".$row["tijd"]."</td><td>".$row["uren"]."</td><td>€".$row["payment"]."</td></tr>";
$total += $row["payment"];
}
echo "Totaal: €".$total;