Question

我有两个约会

$start_date = '2015-09-21';
$end_Date = '2016-09-21';

我想要的是什么

Week  =  Monday           Friday 
36    =  2015-09-21       2015-09-25
37    =  2015-09-28       2015-10-02
38    =  2015-10-05       2015-10-09
.
.
38   =  2016-09-19        2016-09-24

日期差异可能是一年或更长。我需要得到的是每周星期一和星期五这个时间间隔之间的日期。

我使用了这种方法

$weeks = array();
    while ($start_date < $end_Date )
    {  
        $weeks[] = date('W', $start_date ); 
        $start_date += strtotime('+1 week', 0);
    }

    function getStartAndEndDate($week, $year)
    {

        $time = strtotime("1 January $year", time());
        $day = date('w', $time);
        $time += ((7*$week)+1-$day)*24*3600;
        $return[0] = date('Y-m-d', $time);
        $time += 6*24*3600;
        $return[1] = date('Y-m-d', $time);
        return $return;
    }

当我调用此功能时，我需要输入周数和年份来获取确切的日期。但我不能在特定的一周获得一年。我可以设法从开始日期或结束日期开始。

    $current_year = date("Y", strtotime($fromdate));

任何人都建议我用周数得到确切的年份

Answer 1

首先，您需要将时间转换为对象，之后计算差异。现在计算给定日期之间的周数。现在是从开始日期开始的几个星期的时间循环，我使用DateInterval('P4D')将日期提前4天，然后再回复两个日期，然后再DateInterval('P3D')完成一周，这将重复。

$start_date = '2015-09-21';
$end_Date = '2016-09-21';

$date1 = new DateTime($start_date);
$date2 = new DateTime($end_Date);
$interval = $date1->diff($date2);

$weeks = floor(($interval->days) / 7);

for($i = 1; $i <= $weeks; $i++){    
    $week = $date1->format("W");
    $date1->add(new DateInterval('P4D'));
    echo $week." = ".$start_date." - ".$date1->format('Y-m-d')."<br/>";
    $date1->add(new DateInterval('P3D'));
    $start_date = $date1->format('Y-m-d');
}

<强>输出：

39 = 2015-09-21 - 2015-09-25
40 = 2015-09-28 - 2015-10-02
41 = 2015-10-05 - 2015-10-09
42 = 2015-10-12 - 2015-10-16
43 = 2015-10-19 - 2015-10-23
44 = 2015-10-26 - 2015-10-30
45 = 2015-11-02 - 2015-11-06
46 = 2015-11-09 - 2015-11-13
47 = 2015-11-16 - 2015-11-20
48 = 2015-11-23 - 2015-11-27
49 = 2015-11-30 - 2015-12-04
50 = 2015-12-07 - 2015-12-11
51 = 2015-12-14 - 2015-12-18
52 = 2015-12-21 - 2015-12-25
53 = 2015-12-28 - 2016-01-01
01 = 2016-01-04 - 2016-01-08
02 = 2016-01-11 - 2016-01-15
03 = 2016-01-18 - 2016-01-22
04 = 2016-01-25 - 2016-01-29
05 = 2016-02-01 - 2016-02-05
06 = 2016-02-08 - 2016-02-12
07 = 2016-02-15 - 2016-02-19
08 = 2016-02-22 - 2016-02-26
09 = 2016-02-29 - 2016-03-04
10 = 2016-03-07 - 2016-03-11
11 = 2016-03-14 - 2016-03-18
12 = 2016-03-21 - 2016-03-25
13 = 2016-03-28 - 2016-04-01
14 = 2016-04-04 - 2016-04-08
15 = 2016-04-11 - 2016-04-15
16 = 2016-04-18 - 2016-04-22
17 = 2016-04-25 - 2016-04-29
18 = 2016-05-02 - 2016-05-06
19 = 2016-05-09 - 2016-05-13
20 = 2016-05-16 - 2016-05-20
21 = 2016-05-23 - 2016-05-27
22 = 2016-05-30 - 2016-06-03
23 = 2016-06-06 - 2016-06-10
24 = 2016-06-13 - 2016-06-17
25 = 2016-06-20 - 2016-06-24
26 = 2016-06-27 - 2016-07-01
27 = 2016-07-04 - 2016-07-08
28 = 2016-07-11 - 2016-07-15
29 = 2016-07-18 - 2016-07-22
30 = 2016-07-25 - 2016-07-29
31 = 2016-08-01 - 2016-08-05
32 = 2016-08-08 - 2016-08-12
33 = 2016-08-15 - 2016-08-19
34 = 2016-08-22 - 2016-08-26
35 = 2016-08-29 - 2016-09-02
36 = 2016-09-05 - 2016-09-09
37 = 2016-09-12 - 2016-09-16

Answer 2

$start_date = '2015-09-21';
$end_Date = '2016-09-21';

$startTime = strtotime($start_date);
$endTime = strtotime($end_Date);

$weeks = array();
$date = new DateTime();
$i=0;
while ($startTime < $endTime) {  
    $weeks[$i]['week'] = date('W', $startTime);
    $weeks[$i]['year'] = date('Y', $startTime); 
    $date->setISODate($weeks[$i]['year'], $weeks[$i]['week']);
    $weeks[$i]['Monday']=$date->format('Y-m-d'); 
    $weeks[$i]['Friday'] = date('Y-m-d',strtotime($weeks[$i]['Monday'] . "+4 days"));
    $startTime += strtotime('+1 week', 0);
    $i++;
}
var_dump($weeks);

如何在两个日期之间获得一周的开始和结束

2 个答案: