Question

我正在尝试将开始日设置为星期六

SET DATEFIRST 6 -- Sets start day to Saturday

然后在本周开始到本周结束之间获取所有GameDate。但它需要在当天完成。例如：如果当天是星期四，而本周末是星期五，我不想这样做：

DECLARE @StartWeek datetime Set @StartWeek = DATEADD(w, 0, DATEADD(w, DATEDIFF(w, 0,GETDATE()), -5))
DECLARE @EndWeek datetime Set @EndWeek = DATEADD(w, 0, DATEADD(w, DATEDIFF(w, 0,GETDATE()), 1))

因为这会使接下来的5天显示出来。如果CurrentDay是星期四，我不希望在接下来的5天内出现。只是每周的GameDates。

这是我到目前为止所得到的：

DECLARE @DateTable Table (DateofWeek Date) -- Creates table
DECLARE @DateToday Date SELECT DAY(GETDATE()) 'Current Day' -- Gets current date

DECLARE @StartWeek datetime Set @StartWeek = DATEADD(w, 0, DATEADD(w, DATEDIFF(w, 0,GETDATE()), -5)) --This is the part thats wrong
DECLARE @EndWeek datetime Set @EndWeek = DATEADD(w, 0, DATEADD(w, DATEDIFF(w, 0,GETDATE()), 1)) --This is the part thats wrong

SET DATEFIRST 6 -- Sets start day to Saturday


SELECT DATEDIFF ( DAY, @DateToday, @EndWeek) AS Diffrence_End
SELECT DATEDIFF ( DAY, @DateToday, @StartWeek) AS Diffrence_Start
    FROM @DateTable

WHILE @DateToday >= @EndWeek AND @DateToday <= @StartWeek -- Shows all gameDates between StartWeek and Endweek
BEGIN   
    SELECT DATEDIFF ( DAY, @DateToday, @EndWeek)
    Insert Into @DateTable



SELECT * 
    FROM @DateTable
END;

一些查询可能是错误的，尤其是最后一部分。

我希望自己清楚明白，如果有任何问题，请不要犹豫，问我！

Answer 1

看看：

-- Sets start day to Saturday
SET DATEFIRST 6 

-- Creates table
DECLARE @DateTable Table ([DateofWeek] date); 

-- StartDate = DATEPART(DW, ... ) = 1
DECLARE @StartDate date; 
SET @StartDate = DATEADD(day, (DATEPART(dw, GETDATE()) - 1) * -1, GETDATE());

-- EndDate = StartDate + 6 days
DECLARE @EndDate date;
SET @EndDate = DATEADD(day, 6, @StartDate);

-- Generates table values
DECLARE @CurrentDate date;
SET @CurrentDate = @StartDate;

WHILE @CurrentDate <= @EndDate
BEGIN
    INSERT INTO @DateTable ([DateofWeek]) VALUES (@CurrentDate);
    SET @CurrentDate = DATEADD(day, 1, @CurrentDate);
END

--Check it
SELECT *, DATENAME(dw, DateOfWeek) as Name FROM @DateTable;

GO

DateofWeek          | Name     
:------------------ | :--------
18/03/2017 00:00:00 | Saturday 
19/03/2017 00:00:00 | Sunday   
20/03/2017 00:00:00 | Monday   
21/03/2017 00:00:00 | Tuesday  
22/03/2017 00:00:00 | Wednesday
23/03/2017 00:00:00 | Thursday 
24/03/2017 00:00:00 | Friday

dbfiddle here

SQL - 获取当前日期与开始和结束之间的所有日期

1 个答案: