Question

到目前为止，我的代码就是这个：

import java.util.Scanner;

public class PG1 {

  public static void main(String[] args) {

    Scanner input = new Scanner (System.in);
    System.out.print("Enter the length of matrix: ");

    //array indicates
    int i = input.nextInt();
    int j = i;

    //declaration,creation, initialization
    double [][] matrix =  new double [i][j];

    //print element in row i
    for (i = 0; i < matrix.length;i++){
      //print element j in row i
      for (j = 0; j < matrix[i].length; j++) {
        System.out.print("The matrix is: " + matrix[i][j]);
      }
      System.out.println();
    }
  }
}

所以基本上，我想根据用户的输入或矩阵的行和列打印0和1。非常感谢您的帮助。

输出：

输入矩阵的长度：4
矩阵：
0 1 1 1 0 0 0 0 0 1 0 0 1 1 1 1
第1行的全0 第3行的所有1 列上没有相同的数字 diagona上没有相同的数字

Answer 1

你可以这样做：

public static void main（String [] args）{

Scanner input = new Scanner (System.in);

System.out.print("Enter the length of matrix: ");

//array indicates
int i = input.nextInt();
int j = i;
int count0s = 0;
int count1s = 0;

//declaration,creation,initialisation
 double [][] matrix =  new double [i][j];

//print element in row i
 for ( i = 0; i < matrix.length;i++){
    //print element j in row i
     for ( j = 0; j < matrix[i].length; j++){
         if(matrix[i][j] == 0){
              count0s++
              System.out.print("The matrix is: " + matrix[i][j]);
          }
         else if(matrix[i][j] == 1){
              count1s++
              System.out.print("The matrix is: " + matrix[i][j]);
          }

     }
     System.out.println("Total no. of 0s="+count0s);
     System.out.println("Total no. of 1s="+count1s);
 }




}

}

Answer 2

如果您不想打印0和1：

    public static void main(String[] args) {
    Scanner input = new Scanner (System.in);
    System.out.print("Enter the length of matrix: ");

    //array indicates
    int i = input.nextInt();
    int j = i;
    int count0s = 0;
    int count1s = 0;

    //declaration,creation,initialisation
     double [][] matrix =  new double [i][j];

    //print element in row i
     for ( i = 0; i < matrix.length;i++){
        //print element j in row i
         for ( j = 0; j < matrix[i].length; j++){
             if(matrix[i][j] == 0)
                  count0s++
             else if(matrix[i][j] == 1)
                  count1s++
         }
     }
       System.out.println("Total no. of 0s="+count0s);
       System.out.println("Total no. of 1s="+count1s);
    }
    }

如何在2D数组中自动打印0和1并计算其中的1和0？

2 个答案: