是的,我知道围绕这个主题有很多线索,但我不是专门针对故障排除的。我正在寻找最佳做法或建议。
我有一个表单,我已将其分隔出不同的点,以允许用户提交最多4张图片+每张图片的说明。所以看起来像
<div class="container" style="margin-left:0px; padding-left:0px;">
<div class="form-group row" style="margin-left:0px;">
<div class="col-md-3 col-sm-6">
<label for="safetyHazard1_notes"><strong>Safety observation 1:</strong></label> <input type="file" name="safetyHazard1" id="safetyHazard1" value=""><br /> <br />
<textarea cols="25" rows="3" id="safetyHazard1_notes" name="safetyHazard1_notes" placeholder="Enter notes for this observation" ></textarea> </div>
<div class="col-md-3 col-sm-6">
<label for="safetyHazard2_notes"><strong>Safety observation 2:</strong></label> <input type="file" name="safetyHazard2" id="safetyHazard2" value=""><br /><br />
<textarea cols="25" rows="3" id="safetyHazard2_notes" name="safetyHazard2_notes" placeholder="Enter notes for this observation" ></textarea> </div>
<div class="col-md-3 col-sm-6">
<label for="safetyHazard3_notes"><strong>Safety observation 3:</strong></label> <input type="file" name="safetyHazard3" id="safetyHazard3" value=""><br /><br />
<textarea cols="25" rows="3" id="safetyHazard2_notes" name="safetyHazard2_notes" placeholder="Enter notes for this observation" ></textarea> </div>
<div class="col-md-3 col-sm-6">
<label for="other_notes"><strong>Other observations:</strong></label> <input type="file" name="otherObservation" id="otherObservation" value=""><br /><br />
<textarea cols="25" rows="3" id="other_notes" name="other_notes" placeholder="Enter notes for this observation" ></textarea> </div>
</div></div>
现在,对于表单处理,我已经让这些上传字段中的第一个正常运行,这就是我要求此社区帮助的地方。这是我的PHP表单处理。
if(isset($_POST["submit"])) {
$target_dir = $_SERVER['DOCUMENT_ROOT'] . '/testing/tim/uploads/';
$target_file = $target_dir . basename($_FILES["safetyHazard1"]["name"]);
$uploadOk = 1;
$imageFileType = pathinfo($target_file,PATHINFO_EXTENSION);
// Check if image file is a actual image or fake image
$check = getimagesize($_FILES["safetyHazard1"]["tmp_name"]);
if($check !== false) {
echo "File is an image - " . $check["mime"] . ".";
$uploadOk = 1;
} else {
echo "File is not an image.";
$uploadOk = 0;
}
// Check if file already exists
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}
// Check file size
if ($_FILES["safetyHazard1"]["size"] > 500000) {
echo "Sorry, your file is too large.";
$uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType != "jpeg"
&& $imageFileType != "gif" ) {
echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
$uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
if (move_uploaded_file($_FILES["safetyHazard1"]["tmp_name"], $target_file)) {
echo "The file ". basename( $_FILES["safetyHazard1"]["name"]). " has been uploaded.";
} else {
echo "Sorry, there was an error uploading your file.";
}
}
对于第一个,一切都按预期工作 - 文件正在上传到我的指定目录,我的数据库正在存储用户上传的文件名。 GREAT!
但是现在当我继续进行剩下的3次上传时,这里的最佳做法是什么?我显然可以多次复制此代码,然后将target_dir
等变量重命名为target_dir1, target_dir2, etc
。或者是否有一个技巧可以让我用safetyHazard[*]
之类的东西一次性使用我的PHP代码。这有意义吗?