C程序错误 - 输出0

Question

我一直试图让这个工作几天，我仍然无法弄清楚错误。当我输出代码时，它会打印，但是它不会找到友好的对（第一个=第二个除数，反之亦然）。

#include <stdio.h>
#include <stdlib.h>
#define _USE_MATH_DEFINES
#include <math.h>

int sumDivisors( int num );

int sumDivisors( int num )
{
  int counter, total;
  for( counter = 1; counter < num; counter++ )
    {
      if( num % counter == 0 )
        {
          total += counter;
        }
    }
  return ( total );
}

int main( void )
{
  int higher, lower, lowx, lowy, x, y, numOfPairs = 0;

  printf( "This program finds all amicable numbers within a range. \n" );
  printf( "Please enter a lower limit: \n" );
  scanf( "%d", &lower );
  printf( "Please enter a higher limit: \n" );
  scanf( "%d", &higher );


  for( lowx = lower; lowx <= higher; lowx++ )
    {
      for( lowy = lower; lowy <= higher; lowy++ )
        {
          if( sumDivisors( lowx ) == sumDivisors( lowy ) )
            {
              numOfPairs++;
              printf( "Pair #%d: (%d, %d)\n", numOfPairs, lowx, lowy );
            }
        }
    }

  printf( "There are %d amicable pairs from %d to %d\n", numOfPairs, lower, higher );
  system("pause");
  return ( 0 );
}

Answer 1

您没有在代码中为total指定任何值：

int sumDivisors( int num )
{
  int counter, total;
  for( counter = 1; counter < num; counter++ )
    {
      if( num % counter == 0 )
        {
            total += counter;
        }
    }
  return ( total );
}

所以它包含垃圾不可预测的值！

应该是：int counter, total = 0;