Question

我有一个巨大的字符串，分为两部分，如下所示：

     {\"Query\":\"blabla"","\"Subject\":\"gagaga"}","   
     {\"Query\":\"lalala\"","\"Subject\":\"rarara\"}","

依此类推......（线条的代表）

我最终需要一个包含这些值的var：

data =“blabla，gagaga”，“lalala，rarara”，....

这是我的代码，但不起作用：

var contentss = JSON.stringify(allFileGenesDetails1);
data="";
var Query1="";
var Subject1="";
// Parse the data

var contentEachLines = contentss.split("\n");
for (var jj = 0; jj < contentEachLines.length; jj++) {
var lineContent = contentEachLines[jj].split("\t");

var divided = lineContent[jj].split(",");
Query1= Query1+ [divided[0]];
Query1 = Query1.replace(/Query|:|{|"|\|/gi, "");

Subject1=Subject1+ divided[1];
Subject1 = Subject1.replace(/Subject|:|{|"|\|/gi, "");
data=data+"'"+ Query1+","+Subject1 +" ' " +"," ;

Answer 1

尝试：

var allFileGenesDetails1 = JSON.parse("[{\"Query\":\"blabla\",\"Subject\":\"gagaga\"},{\"Query\":\"lalala\",\"Subject\":\"rarara\"}]");
var data = "";
for(var i = 0; i < allFileGenesDetails1.length; i++) {
    if((i+1)==allFileGenesDetails1.length)
        data += allFileGenesDetails1[i].Query+","+allFileGenesDetails1[i].Subject;
    else
        data += allFileGenesDetails1[i].Query+","+allFileGenesDetails1[i].Subject+",";
}
console.log(data);

https://jsfiddle.net/murpoeL5/

如何从字符串中获取值

1 个答案: