所以我有一个存储在名为$data
的变量中的数组,如下所示:
["data"]=>
["rows"]=>
array(30) {
[0]=>
array(3) {
[0]=>
string(10) "2016-08-15"
[1]=>
int(0)
[2]=>
int(0)
}
[1]=>
array(3) {
[0]=>
string(10) "2016-08-16"
[1]=>
int(0)
[2]=>
int(0)
}
[2]=>
array(3) {
[0]=>
string(10) "2016-08-17"
[1]=>
int(0)
[2]=>
int(0)
}
[3]=>
array(3) {
[0]=>
string(10) "2016-08-18"
[1]=>
int(0)
[2]=>
int(0)
}
通过使用以下函数,我从数组中获取值:
$subscribersGained = [];
foreach ($data->data->rows as $obj) {
if (isset($obj[1])) {
// add the element to the beginning of the array
array_unshift($subscribersGained, $obj[1]);
}
if(count($subscribersGained) >= 30) {
break;
}
}
$gained = array_map( create_function('$value', 'return (int)$value;'),
$subscribersGained);
echo json_encode($gained);
将它们存储到一个如下所示的json_string中:
[0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
我需要做的是我必须使非0号为负数。所以在这种情况下我想-1而不是1.任何想法如何实现这一点?谢谢你的时间!
答案 0 :(得分:1)
嗯,我发现它最原始的方法是:
foreach($array as $key => $number) {
$array[$key] = 0 - $number;
}
答案 1 :(得分:1)
$gained = array(0,0,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0);
$gained = array_map(function($el) { return 0-$el; }, $gained);
print_r($gained);
//来自@ Dmytrechko的代码