我在这行代码中遇到问题,我想在其中列出所列公司的4种股票价格。我的问题是,虽然我运行它时没有错误,但代码只打印出股票价格应该去的空括号。这是我困惑的根源。
import urllib2
import re
symbolslist = ["aapl","spy","goog","nflx"]
i = 0
while i<len(symbolslist):
url = "http://money.cnn.com/quote/quote.html?symb=' +symbolslist[i] + '"
htmlfile = urllib2.urlopen(url)
htmltext = htmlfile.read()
regex = '<span stream='+symbolslist[i]+' streamformat="ToHundredth" streamfeed="SunGard">(.+?)</span>'
pattern = re.compile(regex)
price = re.findall(pattern,htmltext)
print "the price of", symbolslist[i], " is ", price
i+=1
答案 0 :(得分:1)
因为你没有传递变量:
url = "http://money.cnn.com/quote/quote.html?symb=' +symbolslist[i] + '"
^^^^^
a string not the list element
使用 str.format :
url = "http://money.cnn.com/quote/quote.html?symb={}".format(symbolslist[i])
你也可以直接在列表上迭代,不需要while循环,从不parse html with a regex,使用像bs4这样的html解析,你的正则表达式也是错误的。没有stream="aapl"
等。您想要的是streamformat="ToHundredth"
和streamfeed="SunGard"
;
import urllib2
from bs4 import BeautifulSoup
symbolslist = ["aapl","spy","goog","nflx"]
for symbol in symbolslist:
url = "http://money.cnn.com/quote/quote.html?symb={}".format(symbol)
htmlfile = urllib2.urlopen(url)
soup = BeautifulSoup(htmlfile.read())
price = soup.find("span",streamformat="ToHundredth", streamfeed="SunGard").text
print "the price of {} is {}".format(symbol,price)
您可以查看我们是否运行了代码:
In [1]: import urllib2
In [2]: from bs4 import BeautifulSoup
In [3]: symbols_list = ["aapl", "spy", "goog", "nflx"]
In [4]: for symbol in symbols_list:
...: url = "http://money.cnn.com/quote/quote.html?symb={}".format(symbol)
...: htmlfile = urllib2.urlopen(url)
...: soup = BeautifulSoup(htmlfile.read(), "html.parser")
...: price = soup.find("span",streamformat="ToHundredth", streamfeed="SunGard").text
...: print "the price of {} is {}".format(symbol,price)
...:
the price of aapl is 115.57
the price of spy is 215.28
the price of goog is 771.76
the price of nflx is 97.34
我们得到你想要的东西。