我们GitHub Gist的完整代码我只包括我认为需要显示问题的部分。
执行方法:
public object Execute()
{
var request = createWebRequest();
request.Method = this.Method;
applyPostData(ref request);
request.ContentType = "application/json";
request.UserAgent = "generic-http-dotnet-client/3.5/v1 (gzip)";
var response = (HttpWebResponse)request.GetResponse();
var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
try
{
return JsonConvert.DeserializeObject(responseString);
}
catch (Exception)
{
return new HttpResponse { message = responseString };
}
}
好的,这种方式很有用。然而,我希望能够做的是在调用该方法之后将其转换为适当的对象类型。
var response = (MetaDataResponse)request.Execute();
我知道应该有一些方法可能使用泛型(Wild guess)让我对json DeserializeObject的响应并返回它?
我最终将execute方法的返回类型更改为字符串,并执行此操作。
public class MetaDataRequest : HttpRequestBase
{
public MetaDataResponse MetaDataItems { get; private set; }
public MetaDataRequest() : base(new Uri("https://www.googleapis.com/analytics/v3/metadata/ga/columns"), "GET")
{
this.addParameter("key", "xxxx");
var response = this.Execute();
try
{
MetaDataItems = JsonConvert.DeserializeObject<MetaDataResponse>(response);
}
catch (Exception)
{
var resultsx = new HttpResponse { message = response };
}
}
}
哪个有效,但接缝对我来说很乱。请注意,此项目是 .Net framework 3.5 ,我无法改变它。随意添加您能想到的任何其他标签。
答案 0 :(得分:1)
对类MetaDataRequest使用泛型
class MetadataRequest<T>:HttpRequestBase
{
public T Execute()
{
var request = createWebRequest();
request.Method = this.Method;
applyPostData(ref request);
request.ContentType = "application/json";
request.UserAgent = "generic-http-dotnet-client/3.5/v1 (gzip)";
var response = (HttpWebResponse)request.GetResponse();
var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
return JsonConvert.DeserializeObject<T>(responseString);
}
}
然后,要获取对象,可以像这样调用方法:
MetadataResponse responseObject = (new MetadataRequest<MetadataResponse>()).Execute();
在这种情况下,您可以捕获.Execute()抛出的异常,因为它只能返回null或类型为T的实例。
编辑:您也可以按照Jeremy Holovacs' answer使用通用方法。
答案 1 :(得分:1)
首先,要点是没有处理它的IDisposables,这非常草率。我推荐这样的东西:
public T Execute<T>()
{
var request = createWebRequest();
request.Method = this.Method;
applyPostData(ref request);
request.ContentType = "application/json";
request.UserAgent = "generic-http-dotnet-client/3.5/v1 (gzip)";
using(var response = (HttpWebResponse)request.GetResponse())
using(var stream = response.GetResponseStream())
using(var reader = new StreamReader(stream))
{
try
{
var responseString = reader.ReadToEnd();
return JsonConvert.DeserializeObject<T>(responseString);
}
catch (Exception ex)
{
//log something with ex
return default(T);
}
}
}