Question

这是第一次发布海报，请原谅不幸。

我在sql中有一个查询，为了简单起见，返回持续时间，业务持续时间和受影响的服务。问题在于，如果受影响的服务，有时它在行中有多个值。例如，它可以是'crm，payrol和scheduling'。见下文。

持续时间业务持续时间影响服务 60 40 crm 100 95工资单 70 70调度 50 45 crm，调度，调度

我想要的是该内部每个值的单独行。像这样：

duration    business duration   impacted service
60                 40                  crm
50                 45                  crm
100                95                payroll
50                 45                payroll
70                 70               scheduling
50                 45               scheduling

你会怎么做？

谢谢！

Answer 1

一种方法使用拆分功能。 Google＆＃34; SQL Server拆分功能＆＃34;在网上。然后你将有一个分割功能。

然后，您可以使用outer apply执行此操作：

select t.duration, t.business_duration, s.impacted_service
from t outer apply
     (dbo.split(t.impacted_service)) s(impacted_service);

Answer 2

这是另一个选项

Declare @YourTable table (duration int,[business duration] int,[impacted service] varchar(50))
Insert Into @YourTable values
(60 ,40,'crm'),
(100,95,'payroll'),
(70 ,70,'scheduling'),
(50 ,45,'crm,payroll, scheduling')

Select Distinct 
       A.duration
      ,A.[business duration]
     ,[impacted service] = B.Key_Value
 From  @YourTable A
 Cross Apply (Select * from [dbo].[udf-Str-Parse](A.[impacted service],',')) B

返回

duration    business duration   impacted service
50          45                  crm
50          45                  payroll
50          45                  scheduling
60          40                  crm
70          70                  scheduling
100         95                  payroll

如果需要，解析UDF

CREATE FUNCTION [dbo].[udf-Str-Parse] (@String varchar(max),@Delimeter varchar(10))
--Usage: Select * from [dbo].[udf-Str-Parse]('Dog,Cat,House,Car',',')
--       Select * from [dbo].[udf-Str-Parse]('John Cappelletti was here',' ')

    Returns @ReturnTable Table (Key_PS int IDENTITY(1,1), Key_Value varchar(max))
    As
    Begin
       Declare @XML xml;Set @XML = Cast('<x>' + Replace(@String,@Delimeter,'</x><x>')+'</x>' as XML)
       Insert Into @ReturnTable Select ltrim(rtrim(String.value('.', 'varchar(max)'))) FROM @XML.nodes('x') as T(String)
       Return 
    End

将一列拆分成几列

2 个答案: