Question

请帮助，如何将这些代码传输到查询构建器？

SELECT *,
       SUM(used_count),COUNT(code)
FROM promo_codes pc 
LEFT JOIN promo_code_user pcu on pc.id=pcu.`promo_code_id` 
LEFT JOIN promo_code_types pct on pc.`promo_code_type_id`=pct.id 
WHERE (pc.expiry_date >= CURDATE() or pc.expiry_date is NULL) and
      (pct.expiry_date >= CURDATE() or pct.expiry_date is null) 
GROUP BY code
HAVING ( (sum(used_count) < global_max_uses  or sum(used_count) is null) and
       ( count(code) < max_users  or count(code) is null) ) ;

谢谢

Answer 1

我无法测试查询，所以我在运行中尝试了一些东西。

$promo = DB::table('promo_codes')
    ->select(‘*’,DB::raw('SUM(used_count),COUNT(code)'))
    ->leftjoin('promo_code_user','promo_codes.id','=','promo_code_user.promo_code_id')
    ->leftjoin('promo_code_types','promo_codes.promo_code_type_id','=','promo_code_types.id')
    ->where(function ($query) {
            $query->where('promo_codes. expiry_date', '>=',DB::raw('curdate()'))
                  ->orWhereNull('promo_codes.expiry_date');
        })
    ->where(function ($query) {
            $query->where('promo_code_types.expiry_date', '>=', DB::raw('curdate()'))
                  ->orWhereNull('promo_code_types.expiry_date');
        })
    ->groupBy('code')
    ->havingRaw((sum(used_count) < global_max_uses  or sum(used_count) is null) and
   ( count(code) < max_users  or count(code) is null)
)->get();

如果您发现任何错误，请在此处发布，以便为您提供帮助

Answer 2

我对你有个好主意，你可以简单地在laravel中使用这个查询而不进行任何转换，请看这个

$results = DB::select( DB::raw("Write Your Query Here ") );
//this will return an array of results , and you can also add parameters to the query as you like

Laravel 5.1通过拥有或拥有使用计数，总和，分组

2 个答案: