在Laravel

Question

我有以下范围：

public function scopeFilterByAmenities($query, AmenityFilters $amenities)
{        
    $ids = DB::table('property_amenities')->distinct()
        ->where(function($query) use ($amenities){
            $query->whereIn('amenity_id', $amenities->ids_enabled());
            $query->where('status', $amenities->enabled_value);
        })
        ->orWhere(function($query) use ($amenities){
            $query->whereIn('amenity_id', $amenities->ids_disabled());
            $query->where('status', $amenities->disabled_value);
        })
        ->groupBy('property_id')
        ->havingRaw('count(*) = '.$amenities->count()) // sum of $amenities->ids_enabled() and $amenities->ids_disabled()
        ->pluck('property_id');

    return $query->whereIn('id', $ids);
}

使用Laravel ORM返回相同的结果不应该是更简单的方法吗？我已经设法以这种方式做了但从我的角度看起来很混乱，Laravel也有内置的东西所以可以让事情更清楚吗？