Question

我有一个按=参数拆分的网址，我想做的是在每个=之后将字符插入数组：

例如：

http://multiplexstimulator.com/catalog/product.php?cat_id=82&pid=157&view=print

应该用等号分成一个如下所示的数组：

["http://multiplexstimulator.com/catalog/product.php?cat_id", "=", "82&pid", "=", "157&view", "=", "print"]

然后我想添加字母＆＃34; a＆＃34;在等号后：

["http://multiplexstimulator.com/catalog/product.php?cat_id", "=", "a", "82&pid", "=", "a", "157&view", "=", "a", "print"]

完成此操作后，我想要join输出该数组：

"http://multiplexstimulator.com/catalog/product.php?cat_id=a82&pid=a157&view=aprint"

我尝试过的事情：

module MultipleParameters

  class TestAllParameters

    def check_for_multiple_parameters(site, char)
      site_arr = []
      if site.count("=") != 1
        site.split("=").each do |string_split|
          site_arr.push(string_split)
        end
      end

      inject_syntax(site_arr, char)
    end

    def inject_character(array, char)
      array.each do |param|
        param.inject(char)
      end

      puts array.join("")
    end

  end

end

然而，当我这样做时，我收到了错误：

detection.rb:18:in `block in inject_syntax': undefined method `inject' for "http://multiplexstimulator.com/catalog/product.php?cat_id":String (NoMethodError)
Did you mean?  inspect
        from detection.rb:17:in `each'
        from detection.rb:17:in `inject_syntax'
        from detection.rb:13:in `check_for_multiple_parameters'
        from detection.rb:33:in `<main>'

如何成功完成此操作？我是否需要scan字符串并将其拆分为＆＃34; =＆＃34;找到而不是用等号分割字符串？

Answer 1

您可以使用#include <stdio.h> #include <string.h> #include <omp.h> #define N 20 int main() { int x[N+1]; for(int i=0; i<N; i++) x[i] = i+1; for(int i=0; i<N; i++) printf("%d ", x[i]); puts(""); #pragma omp parallel { int ithread = omp_get_thread_num(), nthreads = omp_get_num_threads(); size_t pos = ithread*N/nthreads; size_t n = (ithread+1)*N/nthreads - pos - 1; int tmp = x[pos+n]; memmove(&x[pos+1], &x[pos], sizeof *x*n); #pragma omp barrier x[pos+n+1] = tmp; } for(int i=0; i<N+1; i++) printf("%d ", x[i]); puts(""); }方法。

gsub

这会产生

str = 'http://multiplexstimulator.com/catalog/product.php?cat_id=82&pid=157&view=print'

str.gsub('=','=a')

请注意"http://multiplexstimulator.com/catalog/product.php?cat_id=a82&pid=a157&view=aprint"不会修改原始字符串，如果要修改它，请使用gsub

Answer 2

首先，您应该将params与url分开

url = 'http://multiplexstimulator.com/catalog/product.php?cat_id=82&pid=157&view=print'

array = url.split('/')

现在你应该改变所有＆＃39; =＆＃39;到＆＃39; = a＆＃39;在此数组的最后一个元素

array[-1] = array[-1].gsub('=', '=a')

现在你可以在这个数组上使用join：）

new_url = array.join('')

如何将字符注入数组，并将该数组连接到字符串？

2 个答案: