我是C的新手，我正在尝试制作一个骰子游戏。我正在尝试学习指针，并且需要一些关于使用在main中初始化的调用函数和指针的提示和建议。
我在第一次点名功能上得到并错误，以确定第一个滚筒：
名为object＆quot; first_roll_call＆＃39;不是函数或函数指针
这是什么意思，我该如何解决？
这是我的代码：
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main () {
int dice;
int roll, first_roll;
int i;
int first_roll_call;
int *playerA;
int *playerB;
int *first_rollA;
int *first_rollB;
playerA = (int *)malloc(100);
playerB = (int *)malloc(100);
first_rollA = (int *)malloc(100);
first_rollB = (int *)malloc(100);
printf("Welcome to Dice Mania!\n\n");
printf("First player to a combined score of 25 wins!\n");
printf("We to see who goes first, press 1 to continue:");
scanf("%d", &first_roll);
for (i = 1; i < 2; i++){
first_roll = rand() % 6 + 1;
first_roll_call(first_roll, i, &first_rollA, &first_rollB);
}
if (*first_rollA > *first_rollB){
printf("Player 1 goes first!\n");
}
else {
printf("Player 2 goes first!\n");
}
if (dice == 1) {
while (dice == 1) {
printf("Please press 1 to initiate the dice roll, 0 to exit\n\n");
srand(time(NULL));
roll = rand() % 6 + 1;
printf("You have rolled a: \n\n");
dice = dice_roll(roll);
if (dice == 0) {
printf("\n\nThank you for playing");
break;
}
}
}
return 0;
}
int dice_roll(int x) {
int dice;
if (x == 1) {
printf("*************\n");
printf("* ----- *\n");
printf("* | *\n");
printf("* | *\n");
printf("* | *\n");
printf("* | *\n");
printf("* ------- *\n");
printf("*************\n");
printf("Please press 1 to initiate the dice roll, 0 to exit\n\n");
scanf("%d", &dice);
return(dice);
}
if (x == 2) {
int dice;
printf("*************\n");
printf("* _____ *\n");
printf("* | *\n");
printf("* ____| *\n");
printf("* | *\n");
printf("* |____ *\n");
printf("* *\n");
printf("*************\n");
printf("Please press 1 to initiate the dice roll, 0 to exit\n\n");
scanf("%d", &dice);
return(dice);
}
if (x == 3) {
int dice;
printf("*************\n");
printf("* ----- *\n");
printf("* | *\n");
printf("* ___| *\n");
printf("* | *\n");
printf("* | *\n");
printf("* ----- *\n");
printf("*************\n");
printf("Please press 1 to initiate the dice roll, 0 to exit\n\n");
scanf("%d", &dice);
return(dice);
}
if (x == 4) {
int dice;
printf("*************\n");
printf("* | | *\n");
printf("* | | *\n");
printf("* |____| *\n");
printf("* | *\n");
printf("* | *\n");
printf("* | *\n");
printf("*************\n*");
printf("Please press 1 to initiate the dice roll, 0 to exit\n\n");
scanf("%d", &dice);
return(dice);
}
if (x == 5) {
int dice;
printf("*************\n");
printf("* _____ *\n");
printf("* | *\n");
printf("* |____ *\n");
printf("* | *\n");
printf("* _____| *\n");
printf("* *\n");
printf("*************\n");
printf("Please press 1 to initiate the dice roll, 0 to exit\n\n");
scanf("%d", &dice);
return(dice);
}
if (x == 6) {
int dice;
printf("*************\n");
printf("* _____ *\n");
printf("* | *\n");
printf("* |____ *\n");
printf("* | | *\n");
printf("* |____| *\n");
printf("* *\n");
printf("*************\n");
printf("Please press 1 to initiate the dice roll, 0 to exit\n\n");
scanf("%d", &dice);
return(dice);
}
int first_roll_call(int x, int y, int *first_rollA, int *first_rollB){
int dice;
if (x == 1) {
printf("*************\n");
printf("* ----- *\n");
printf("* | *\n");
printf("* | *\n");
printf("* | *\n");
printf("* | *\n");
printf("* ------- *\n");
printf("*************\n");
if (y = 1){
printf("Player one rolled a %d", x);
x = *first_rollA;
}
if (y = 2) {
printf("Player two rolled a %d", x);
x = *first_rollB;
}
}
if (x == 2) {
int dice;
printf("*************\n");
printf("* _____ *\n");
printf("* | *\n");
printf("* ____| *\n");
printf("* | *\n");
printf("* |____ *\n");
printf("* *\n");
printf("*************\n");
if (y = 1) {
printf("Player one rolled a %d", x);
x = *first_rollA;
}
if (y = 2) {
printf("Player two rolled a %d", x);
x = *first_rollB;
}
}
if (x == 3) {
int dice;
printf("*************\n");
printf("* ----- *\n");
printf("* | *\n");
printf("* ___| *\n");
printf("* | *\n");
printf("* | *\n");
printf("* ----- *\n");
printf("*************\n");
if (y = 1){
printf("Player one rolled a %d", x);
x = *first_rollA;
}
if (y = 2) {
printf("Player two rolled a %d", x);
x = *first_rollB;
}
}
if (x == 4) {
int dice;
printf("*************\n");
printf("* | | *\n");
printf("* | | *\n");
printf("* |____| *\n");
printf("* | *\n");
printf("* | *\n");
printf("* | *\n");
printf("*************\n*");
if (y = 1) {
printf("Player one rolled a %d", x);
x = *first_rollA;
}
if (y = 2) {
printf("Player two rolled a %d", x);
x = *first_rollB;
}
}
if (x == 5) {
int dice;
printf("*************\n");
printf("* _____ *\n");
printf("* | *\n");
printf("* |____ *\n");
printf("* | *\n");
printf("* _____| *\n");
printf("* *\n");
printf("*************\n");
if (y = 1) {
printf("Player one rolled a %d", x);
x = *first_rollA;
}
if (y = 2) {
printf("Player two rolled a %d", x);
x = *first_rollB;
}
}
if(x == 6) {
int dice;
printf("*************\n");
printf("* _____ *\n");
printf("* | *\n");
printf("* |____ *\n");
printf("* | | *\n");
printf("* |____| *\n");
printf("* *\n");
printf("*************\n");
if (y = 1) {
printf("Player one rolled a %d", x);
x = *first_rollA;
}
if (y = 2) {
printf("Player two rolled a %d", x);
x = *first_rollB;
}
}
}
}
答案 0 :(得分：4)
编译器抱怨main()中的这一行：
first_roll_call(first_roll, i, &first_rollA, &first_rollB);
它抱怨first_roll_call不是一个功能是完全正确的。在main()早期，您声明它是int类型的局部变量：
int first_roll_call;
在main()内，该声明会影响同名的任何其他对象。如果你想将它声明为函数返回 int，那么至少你需要这个，而不是：
int first_roll_call();
但是，你应该为该函数声明一个完整的原型：
int first_roll_call(int, int, int *, int *);
此外，虽然允许在其他函数中声明函数（但不来嵌套函数体！），但是将函数声明放在文件范围内，靠近顶部的函数声明更为常见。源文件。
对于这样一个相当简单的情况，将函数main()移动到源文件的末尾将不再需要它来声明其他函数。编译器在到达main()时已经看到了附加到它们的函数体的声明，这些声明已经足够了。
答案 1 :(得分：1)
在C中，您必须先声明一个函数，然后才能使用它。编译器严格从上到下读取源代码。
因此，要么将整个first_roll_call函数移动到文件的顶部，要么在文件顶部写下以下行。
int first_roll_call(int x, int y, int *first_rollA, int *first_rollB);
此行声明了该函数，但保留了定义以供日后使用。