我正在为低通滤波器编写程序。当我编译时,我收到以下错误:
被调用对象不是函数或函数指针
我用double声明的变量。知道为什么会这样吗?
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(int argc, char **argv) {
double omega1, omega2, omegac, T, dt;
int N, method;
FILE *in;
// Open the file and scan the input variables.
if (argv[1] == NULL) {
printf("You need an input file.\n");
return -1;
}
in = fopen(argv[1], "r");
if (in == NULL)
return -1;
fscanf(in, "%lf", &omega1);
fscanf(in, "%lf", &omega2);
fscanf(in, "%lf", &omegac);
fscanf(in, "%d", &method);
T = 3 * 2 * M_PI / omega1; // Total time
N = 20 * T / (2 * M_PI / omega2); // Total number of time steps
dt = T / N; // Time step ("delta t")
// Method number 1 corresponds to the finite difference method.
if (method == 1) {
int i;
double Voutnew = 0, Voutcur = 0, Voutprev = 0;
for (i = N; i != 0; i--) {
Voutnew = ((1/((1/((sqrt(2))(dt)(omegac))) + (1/((dt)(dt)(omegac) (omegac))))) * (((2/((dt)(dt)(omegac)(omegac))) - 1)(Voutcur) + (1/((1/((sqrt(2))(dt)(omegac))) - (1/((dt)(dt)(omegac)(omegac)))))(Voutprev) + Sin((omega1)(T)) + (1/2)(Sin((omega2)(T)))));
Voutcur = Voutnew; // updates variable
Voutprev = Voutcur; // passes down variable to next state
printf("%lf\n", Voutnew);
}
} else {
// Print error message.
printf("Incorrect method number.\n");
return -1;
}
fclose(in);
return 0;
}
以下是我收到的错误列表:
In function 'main':
Line 38: error: called object '1.41421356237309514547462185873882845044136047363e+0' is not a function
Line 38: error: called object 'dt' is not a function
Line 38: error: called object 'dt' is not a function
Line 38: error: called object '1.41421356237309514547462185873882845044136047363e+0' is not a function
Line 38: error: called object 'dt' is not a function
Line 38: error: called object 'omega1' is not a function
Line 38: error: called object 'omega2' is not a function
Line 38: error: called object '0' is not a function
答案 0 :(得分:1)
您需要乘法运算符
((sqrt(2))(dt)(omegac)
例如,是错误的,您应该在我至少知道的所有编程语言中明确指定乘法运算符
sqrt(2) * dt * omegac
另外,使用太多括号会使您的代码难以阅读,所以不要这样做。
自
以来,错误消息就是使用括号(dt)(omegac)
被解释为dt
是一个函数而omegac
是一个传递给它的参数,并且由于dt
不是函数,因此错误消息是有意义的。
这只是需要修复的代码的一小部分,如果我是你,我会在子表达式中分割表达式,在你所拥有的大型表达式中看到错误并不容易那里。
对Sin
的未定义引用是因为c区分大小写,没有名为Sin
的函数,它是sin
。