当我尝试从php页面获取数据时,我在swift上遇到此Error Domain=NSCocoaErrorDomain Code=3840 "Garbage at end." UserInfo={NSDebugDescription=Garbage at end.}
错误
这是php代码
require ('database.php');
function get_msg()
{
global $connection;
$query = "SELECT `sender`,`message` FROM `simply`.`chat_experimetn` WHERE `sender` = 'ken' || `sender` = 'jen' ";
$result = mysqli_query($connection,$query);
$messages = array();
while($message = mysqli_fetch_assoc($result))
{
$messages[] = array('sender'=>$message['sender'],'message'=>$message['message']);
}
echo json_encode($messages);
return $messages;
} this is what the array look like in localhost
这是快速代码
var values:NSArray = []
override func viewDidLoad() {
super.viewDidLoad()
get();
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func get(){
let url = NSURL(string: "http://localhost/training_site/php/index.php")
let data = NSData(contentsOfURL: url!)
do{
values = try NSJSONSerialization.JSONObjectWithData(data!, options: NSJSONReadingOptions.MutableContainers) as! NSArray
tableView.reloadData()
}catch{
print(error)
}
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return values.count;
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("cell", forIndexPath: indexPath) as! SpecialCell
let maindata = values[indexPath.row]
cell.username.text = maindata["sender"] as? String
cell.password.text = maindata["message"] as? String
//cell.num.text = maindata["FavoriteNumber"] as? String
//cell.info.text = maindata["Info"] as? String
return cell;
}
我无法找到解决方案。这是我最后的希望,请帮助。