我有一个使用php和jQuery创建的多行动态表。这是the link to view the table。
一切正常,除非我将数据插入数据库,序列号不会按顺序保存。我的插入查询如下:
for($i = 0; $i < count($_POST['C_Objectives']); $i++)
{
$sql = "INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,Measures,Targets,subtotal,Corporate_Objective,Row_Number,ID) Values ('$formno','||<==','==','==','".$_POST['SubTotals'][$i]."','".$_POST['C_Objectives'][$i]."','".$_POST['SNo'][$i]."','$statement')";
$stmt = sqlsrv_query($conn, $sql);
if($stmt === false)
die(print_r(sqlsrv_errors(), true));
else
echo " ";
}
for($i = 0; $i < count($_POST['Measures']); $i++)
{
$sql = "INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,Measures,Targets,Weightage,Row_Number,target_date,ID) VALUES ('$formno','".$_POST['Objectives'][$i]."','".$_POST['Measures'][$i]."','".$_POST['Achievement'][$i]."','".$_POST['Weightage_Target'][$i]."','".$_POST['SNo'][$i]."','".$_POST['Date_Target'][$i]."','$statement')";
$stmt = sqlsrv_query($conn, $sql);
if($stmt === false)
die(print_r(sqlsrv_errors(), true));
else
echo " ";
}
序列号使用$_POST['SNo'][$i]
保存在 Row_Number列中。是否可以使用1个插入查询保存两个动态行,以便顺序保存序列号?
这是$_POST
数组结果:
[Row_Number] => Array
(
[0] => 1
[1] => 2
)
[C_Objectives] => Array
(
[0] => A
[1] => B
)
[Objectives] => Array
(
[0] => a1
[1] => a4
[2] => a7
[3] => b1
)
[Measures] => Array
(
[0] => a2
[1] => a5
[2] => a8
[3] => b2
)
[Achievement] => Array
(
[0] => a3
[1] => a6
[2] => a9
[3] => b3
)
[Date_Target] => Array
(
[0] => 2016-09-09
[1] => 2016-09-09
[2] => 2016-09-09
[3] => 2016-09-09
)
[Weightage_Target] => Array
(
[0] => 25
[1] => 25
[2] => 25
[3] => 25
)
[SNo] => Array
(
[0] => 3
[1] => 4
[2] => 5
[3] => 6
)
[SubTotals] => Array
(
[0] => 75
[1] => 25
)
[GrandTotal] => 100
)
我也尝试使列自动递增,但是不按照在前端输入的顺序保存数据。
答案 0 :(得分:5)
您的插入存在性能问题。请更改插入数据库的方式。您可以在一个查询中执行所有这些操作。即使你有第一个“for”的20个循环和第二个“for”的20个循环。
回答您提出的问题
如果您想按$ _POST ['SNo']顺序插入,请更改此行
for($i = 0; $i < count($_POST['C_Objectives']); $i++)
到
foreach($_POST['SNo'] as $i)
如果您需要一次插入多个插件,请执行以下操作:
INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,...)
VALUES (Value1,Value2,...), (Value1,Value2,...)
这是你必须做的事
在您的代码中,您在6个查询中执行了相同的查询。它甚至可以超过6个更多$ _POST ['Measures']或$ _POST ['C_Objectives']数组长度。 您需要将它们放在一个查询中,当您不需要设置该值时,只需将其设置为列默认值即可。例如NULL
这样的事情:
//first we create $values array. it contains all values that you need to insert to the db
$values = array();
$j=0;
for($i = 0; $i < count($_POST['C_Objectives']); $i++){
$values[$j]['Serial_Number'] = $formno;
$values[$j]['Objectives'] = '||<==';
//and fill others here
//fill all cols that you wrote inside your query with the correct order
$j++;
}
for($i = 0; $i < count($_POST['Measures']); $i++){
$values[$j]['Serial_Number'] = $formno;
$values[$j]['Objectives'] = $_POST['Objectives'][$i];
//and fill others here
//fill all cols that you wrote inside your query with the correct order
$j++;
}
//now create (value1,value2,...),(value1,value2,...),...
$query = NULL;
foreach($values as $value){
$tmp = NULL;
foreach($value as $v){
$tmp .= ($v=='')? 'NULL,' : "'$v',";
}
$tmp = rtrim($tmp,',');
$query .= "($tmp),";
}
$query = rtrim($query,',');
//Now Insert
$sql = "INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,...) VALUES $query";
在这个例子中,我只是告诉你如何做到这一点。请记住,您必须检查$ v并按列类型进行准备。检查是否设置了$_POST[KEY]
和它的数组。如果$query
为空,请勿插入数据库。
非常重要的代码
如果这不是您的原始代码,则没有问题,但如果是,请更改您在查询中使用$ _POST的方式。它的安全性很低。至少你需要在使用之前验证它们。
答案 1 :(得分:0)
是的,您可以在单个插入查询中插入。
$arrMeasuresInsData = array();
for($i = 0; $i < count($_POST['C_Objectives']); $i++) {
$sql = "INSERT INTO Appraisal_Objectives (Serial_Number, Objectives, Measures, Targets, subtotal, Corporate_Objective, Row_Number, ID, Weightagen, target_date)
Values ('$formno',
'||<==',
'==',
'==',
'".$_POST['SubTotals'][$i]."',
'".$_POST['C_Objectives'][$i]."',
'".$_POST['SNo'][$i]."',
'$statement',
'',
'')";
if(!empty($_POST['Measures'][$i])) {
$arrMeasuresInsData[$i] = $_POST['Measures'][$i];
$sql .= ",('$formno',
'".$_POST['Objectives'][$i]."',
'".$_POST['Measures'][$i]."',
'".$_POST['Achievement'][$i]."',
'',
'',
'".$_POST['SNo'][$i]."',
'".$_POST['Date_Target'][$i]."',
'".$_POST['Weightage_Target'][$i]."',
'$statement',)";
}
$stmt = sqlsrv_query($conn, $sql);
if($stmt === false)
{
die(print_r(sqlsrv_errors(), true));
}
else
{
echo " ";
}
}
for($i = 0; $i < count($_POST['Measures']); $i++) {
if(isset($arrMeasuresInsData[$i])) {
continue;
}
$sql="INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,Measures,Targets,Weightage,Row_Number,target_date,ID)
VALUES ('$formno',
'".$_POST['Objectives'][$i]."',
'".$_POST['Measures'][$i]."',
'".$_POST['Achievement'][$i]."',
'".$_POST['Weightage_Target'][$i]."',
'".$_POST['SNo'][$i]."',
'".$_POST['Date_Target'][$i]."',
'$statement')";
$stmt = sqlsrv_query($conn, $sql);
if($stmt === false)
{
die(print_r(sqlsrv_errors(), true));
}
else
{
echo " ";
}
}
答案 2 :(得分:0)
我认为你错误地获得了$ _POST数组。您必须更改输入表单并接收输入,如下所示:
[C_Objectives] => Array
(
[Row_Number] => Array
(
[title] => 'xxx',
[0] => Array
(
[0] => Array
(
[SNo] => 2
[Objectives] => a1,
[Measures] => a2,
[Achievement] => a3,
[Date_Target] => 2016-09-09,
[Weightage_Target] => 25
),
(
[SNo] => 3
[Objectives] => a1,
[Measures] => a2,
[Achievement] => a3,
[Date_Target] => 2016-09-09,
[Weightage_Target] => 25
),
(
[SNo] => 4
[Objectives] => a1,
[Measures] => a2,
[Achievement] => a3,
[Date_Target] => 2016-09-09,
[Weightage_Target] => 25
),
[SubTotals] => 75
)
)
},
(
[Row_Number] => Array
(
[title] => 'xxx',
[0] => Array
(
[0] => Array
(
[SNo] => 6
[Objectives] => a1,
[Measures] => a2,
[Achievement] => a3,
[Date_Target] => 2016-09-09,
[Weightage_Target] => 25
),
[SubTotals] => 25
)
)
)
以上是您必须了解如何做到这一点的唯一示例。
因为知道哪个值属于哪一行是很困难的,所以可能将该值定义为第二行到第三行。
答案 3 :(得分:0)
使用当前代码时,至少会有两个 INSERT 语句,当$_POST['Measures']
或$_POST['C_Objectives']
包含更多元素时,会有更多语句。
您可以使用一个语句插入多个记录,而不是使用 for 语句,使用 foreach ,这样您就不必在迭代器上进行簿记变量。然后将值存储在数组中,并使用implode()组合每个记录的值集。
检查哪些值插入到哪些列中 - 看起来在示例的第一个 for 循环中,您将$_POST['SNo'][$i]
中的值插入ID字段...
$values = array();
foreach($_POST['C_Objectives'] as $index=>$value) {
$rowValues = array();
$rowValues[] = $_POST['SNo'][$index]; //Serial_Number
array_push($rowValues,$formno,'||<==','==','=='); //, Objectives, Measures, Targets, subtotal
$rowValues[] = $_POST['SubTotals'][$index]; //Corporate_Objective
$rowValues[] = $value; //Row_Number: $value == $_POST['C_Objectives'][$index];
$values[] = "('".implode("', '",$rowValues )."')";
}
$fields = array('Objectives','Measures','Achievement','Weightage_Target','SNo','Date_Target');
foreach($_POST['Measures'] as $index=>$value) {
$rowValues = array($formno);
foreach($fields as $field) {
$rowValues[] = $_POST[$field][$index];
}
$values[] = "('".implode("', '",$rowValues )."')";
}
$sql = "INSERT INTO Appraisal_Objectives (Serial_Number,Objectives,Measures,Targets,subtotal,Corporate_Objective,Row_Number,ID) VALUES ".implode(', ',$values);
$stmt = sqlsrv_query($conn, $sql);
if($stmt === false) {
die(print_r(sqlsrv_errors(), true));
}
else {
echo " ";
}
答案 4 :(得分:-1)
解决方案: 1.第二次更新操作。 2.立即将数据整理到数据库中。