Question

我有一个帐户表，其中一个名为＆＃34; dateCreation＆＃34;是创建帐户的日期。

我想在过去12个月内获得所有创建的帐户，但有时在2个月或更长时间内没有创建帐户。对于这几个月，我觉得mysql会返回0.我的请求工作正常（我在stackoverflow上得到它）：

 SELECT  customers.dateCreation, Months.id AS `month`, Months.mois, COUNT(customers.dateCreation) AS `count`
FROM 
(
  SELECT 1 as ID, 'Janvier' as mois UNION SELECT 2 as ID, 'Février' as mois UNION  SELECT 3 as ID, 'Mars' as mois UNION SELECT 4 as ID, 'Avril' as mois 
  UNION  
  SELECT 5 as ID, 'Mai' as mois UNION SELECT 6 as ID, 'Juin' as mois UNION SELECT 7 as ID, 'Juillet' as mois UNION SELECT 8 as ID , 'Aout' as mois
  UNION  
  SELECT 9 as ID, 'Septembre' as mois UNION SELECT 10 as ID, 'Octobre' as mois UNION SELECT 11 as ID, 'Novembre' as mois UNION SELECT 12 as ID, 'Decembre' as mois
) as Months
LEFT JOIN customers on Months.id=month(customers.dateCreation) AND dateCreation BETWEEN Date_add(Now(),interval - 12 month) AND NOW()
GROUP BY Months.id
ORDER BY Months.id ASC

但它会返回类似的内容：

    ID    |    Count
    1     |      0
    2     |      0
    3     |      0
    4     |      0
    5     |      8
    6     |      1
    7     |      0
    8     |      1
    9     |      0
    10    |      7
    11    |      0
    12    |      4

但我们9月份，所以我希望第一个月是10月

这是一个sqlfiddle：http://sqlfiddle.com/#!9/edfeb/1

Answer 1

将您的订单修改为：

ORDER BY
  CASE WHEN Months.id > MONTH(NOW()) -- check if the month is after the current 
       THEN 0                        -- order by months after the current first
       ELSE 1                        -- and then by the months up to the current 
  END,
  Months.id ASC

请参阅fiddle

Answer 2

请替换左连接尝试此操作：

LEFT JOIN customers ON Months.id=MONTH(customers.dateCreation) 
    AND dateCreation BETWEEN DATE_ADD(CURDATE(),INTERVAL - 12 MONTH) AND CURDATE()

每月创建过去12个月的帐户

2 个答案: