Question

我有一个表REGDATE列，一个注册日期（YYYY-MM-DD HH：MM：SS）。我想显示一个直方图（ExtJS），以了解用户注册的年份。我希望在过去的12个月内对当前日期和按周分组日期这样做。

任何提示？

Answer 1

PostgreSQL中的FWIW，Karaszi有一个有效的答案，但有一个更快的查询：

SELECT date_trunc('week', REGDATE) AS "Week" , count(*) AS "No. of users"
FROM <<TABLE>>
WHERE REGDATE > now() - interval '12 months' 
GROUP BY 1
ORDER BY 1;

我的基础是Ben Goodacre

的工作

Answer 2

MySQL中的

：

SELECT COUNT(*), DATE_FORMAT(regdate, "%X%V") AS regweek FROM table GROUP BY regweek;

或

SELECT COUNT(*), YEARWEEK(NOW(), 2) as regweek FROM table GROUP BY regweek;

PostgreSQL中的

：

SELECT COUNT(*), EXTRACT(YEAR FROM regdate)::text ||  EXTRACT(WEEK FROM regdate)::text AS regweek FROM table GROUP BY regweek;

Answer 3

也许这个？

select to_char(REGDATE,'WW') "Week number",
       count(*) "number of signups",
from YOUR_TABLE
where REGDATE > current_date-365
group by to_char(REGDATE,'WW')
order by to_char(REGDATE,'WW')

Answer 4

提示：（SQL）

SELECT CONVERT (VARCHAR(7), REGDATE, 120) AS [RegistrationMonth]
FROM ...
GROUP BY CONVERT (VARCHAR(7), REGDATE, 120)
ORDER BY CONVERT (VARCHAR(7), REGDATE, 120)

过去12个月，按周分组

4 个答案: