这是我的问题。我有一个包含2个强实体(事件和员工)的数据库。每个活动都可以有多名员工作为助理,并有一名员工作为领导者。所以我在事件中有一个外键leaderID,并创建了一个连接员工和事件的弱实体助手。
我想要的是显示每个事件的所有员工姓名,adventureCode和startDate以及他们是否是领导者。像:
GR01 2016/09/18 Trudy Lee Leader
GR01 2016/09/18 Sonia Chen Assistant
GR01 2016/09/18 Henry Blake Assistant
YV02 2016/09/17 John Bull Leader
我不知道如何获得额外的第4列,因为它不在数据库中。
CREATE TABLE employee(
empID varchar(5) PRIMARY KEY,
name varchar(30)
);
CREATE TABLE event(
adventureCode varchar(5),
startDate varchar(20),
leaderID varchar(5) NOT NULL,
PRIMARY KEY (adventureCode,startDate),
FOREIGN KEY (leaderID) REFERENCES employee (empID),
FOREIGN KEY (adventureCode) REFERENCES adventure (adventureCode)
);
CREATE TABLE assistant(
empID varchar(10),
startDate varchar(20),
adventureCode varchar(5),
PRIMARY KEY (empID,startDate,adventureCode),
FOREIGN KEY (empID) REFERENCES employee (empID),
FOREIGN KEY (adventureCode,startDate) REFERENCES event (adventureCode,startDate)
);
欢迎任何帮助
答案 0 :(得分:3)
您可以使用CASE EXPRESSION
生成此列COALESCE()
和LEFT JOIN
:
SELECT e.empID,
e.Name,
COALESCE(ev.adventureCode,a.adventure_code) as adventure_code,
COALESCE(ev.startDate,a.startdate) as startdate,
CASE WHEN ev.leaderID IS NOT NULL THEN 'Leader' ELSE 'Assistant' END as pos_col
FROM employee e
LEFT JOIN `event` ev
ON(ev.leaderID = e.empID)
LEFT JOIN assistant a
ON(e.empID = a.empID)