例如,如果是
Student Course
---------------------------
student 1 | Math
--------------------------
student 1 | English
--------------------------
student 1 | Art
--------------------------
student 2 | Math
--------------------------
student 2 | Economics
--------------------------
student 3 | Math
--------------------------
student 3 | English
--------------------------
我想如何基于学生生成课程的索引列,比如
Student Course Index
--------------------------------------------
student 1 | Math | 1
--------------------------------------------
student 1 | English | 2
--------------------------------------------
student 1 | Art | 3
--------------------------------------------
student 2 | Math | 1
--------------------------------------------
student 2 | Economics | 2
--------------------------------------------
student 3 | Math | 1
--------------------------------------------
student 3 | English | 2
--------------------------------------------
所以基本上第二个表上的第3列是当然每个学生的索引/序列,但我希望第二个表成为对第二个表的查询(在Oracle中),只是找不到解决方案。我只能赚钱,而不是索引。
答案 0 :(得分:3)
SELECT Student
,Course
,ROW_NUMBER() OVER (PARTITION BY Student ORDER BY Course DESC) AS "Index"
FROM your_table;
答案 1 :(得分:3)
您需要使用row_number窗口函数。
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