Question

我有以下矩阵：

const double values[3][41] = { { -116.99, -116.99, -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -72.385, -60.657,
        -72.385, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99 }, { -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -97.597, -81.568,
        -74.745, -66.323, -74.745, -81.568, -97.597, -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
        -116.99, -116.99, -116.99, -116.99, -116.99, -116.99 },
        { -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
                -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
                -116.99, -107.26, -97.836, -89.451, -83.642, -78.459, -71.99,
                -78.459, -83.642, -89.451, -97.836, -107.26, -116.99, -116.99,
                -116.99, -116.99, -116.99, -116.99, -116.99, -116.99, -116.99,
                -116.99, -116.99, -116.99, -116.99, -116.99, -116.99 }}

是否可以快速将其转换为values[3][41]，同时保留值的正确性

这些值来自设备，该设备将输出写为[y][x]而不是[x][y]。我写了一个包装函数来调用矩阵中的值，但也许有一种方法可以反转轴。

Answer 1

你只需要循环它：

const double values[3][41] = {...};
double newValues[41][3];

for(int i=0; i<3; ++i) {
    for(int j=0; j<41; ++i) {
        newValues[j][i] = values[i][j];
    }
}

但是，这需要两倍的内存空间。也可以在内存中重新排序。

如何反转矩阵的尺寸（相互之间）？

1 个答案: