Question

我试图卷曲网页并对其进行一些处理，最后我尝试以json格式打印。（实际上需要在mongodb输入中）

所以输入（通过卷曲读取）是

输入：

brendan google engineer
stones microsoft chief_engineer
david facebook tester

对于处理类型，我为变量赋值（$ name，$ emloyer，$ designation）

我转换为json的最终命令是，

echo [{\"Name\":\"$name\"},{\"Employer\":\"$employer\"},{\"dDesignation\":\"$designation\"}]

当前输出为

[{"Name":"brendan","Employer":"google","Designation":"engineer"}]
[{"Name":"stones","Employer":"microsoft","Designation":"chief_engineer"}]
[{"Name":"david","Employer":"facebook","Designation":"tester"}]

但是，我希望同一行中的输出在开头和结尾用逗号和方括号分隔（不是在每一行）

预期输出：

  [{"Name":"brendan","Employer":"google","Designation":"engineer"},{"Name":"stones","Employer":"microsoft","Designation":"chief_engineer"},
    {"Name":"david","Employer":"facebook","Designation":"tester"}]

任何建议。

Answer 1

传统的文本处理工具无法针对一般情况执行此操作。 JSON有很多极端案例 - 例如，需要转义非打印和高Unicode字符（和引号）。使用实际为作业构建的工具，例如jq：

jq -n -R '
[
  inputs |
  split(" ") |
  { "Name": .[0], "Employer": .[1], "Designation": .[2] }
]' <<EOF
brendan google engineer
stones microsoft chief_engineer
david facebook tester
EOF

...作为输出发出：

[
  {
    "Name": "brendan",
    "Employer": "google",
    "Designation": "engineer"
  },
  {
    "Name": "stones",
    "Employer": "microsoft",
    "Designation": "chief_engineer"
  },
  {
    "Name": "david",
    "Employer": "facebook",
    "Designation": "tester"
  }
]

Answer 2

这样的东西？

sep='['
curl "...whatever..." |
while read -r name employer designation; do
    printf '%s{"Name": "%s", "Employer": "%s", "Designation": "%s"}' "$sep" "$name" "$employer" "$designation"
    sep=', '
done
printf ']\n'

我确实认为这很脆弱且容易出错;如果您可以使用像jq这样的JSON感知工具，请务必这样做。

Answer 3

如果您有权访问jq 1.5或更高版本，那么您可以使用inputs，并且如果令牌可能被多个空格分隔，可能会考虑使用splits(" +")：

jq -n -R '
  [inputs
   | [splits(" +")]
   | { "Name": .[0], "Employer": .[1], "Designation": .[2] }]'

如果您没有准备好访问jq 1.5或更高版本，请注意以下内容适用于jq 1.4：

jq -R -s '
  [split("\n")[]
   | select(length>0)
   | split(" ")
   | { "Name": .[0], "Employer": .[1], "Designation": .[2] }]'

Bash脚本以json格式打印输出

3 个答案: