我在Java中有以下HTTP JSON响应,它代表一个用户对象。
{
"account": "Kpatrick",
"firstname": "Patrick",
[
],
"instances":
[
{
"id": "packerer-pool",
"key": "packerer-pool123",
"userAccount": "kpatrick",
"firstname": "Patrick",
"lastname": "Schmidt",
}
],
"projects":
[
{
"id": "packerer-projectPool",
"projectKey": "projectPool-Pool",
"cqprojectName": "xxxxx",
},
{
"id": "packerer-secondproject",
"projectKey": "projectPool-Pool2",
"cqprojectName": "xxxx",
},
{
"id": "packerer-thirdproject",
"projectKey": "projectPool-Pool3",
"cqprojectName": "xxxx",
}
],
"clients":
[
],
"dbid": 76864576,
"version": 1,
"id": "dbpack21"
}
现在,我希望在projectkey
的帮助下搜索特定项目(例如" projectPool-Pool2")。之后,我想完全删除该元素。因为我的目标是在没有这个项目的情况下发送HTTP后呼叫。
对于我的HTTP后呼叫,结果应类似于以下内容:
{
"account": "Kpatrick",
"firstname": "Patrick",
[
],
"instances":
[
{
"id": "packerer-pool",
"key": "packerer-pool123",
"userAccount": "kpatrick",
"firstname": "Patrick",
"lastname": "Schmidt",
}
],
"projects":
[
{
"id": "packerer-projectPool",
"projectKey": "projectPool-Pool",
"cqprojectName": "xxxxx",
},
{
"id": "packerer-thirdproject",
"projectKey": "projectPool-Pool3",
"cqprojectName": "xxxx",
}
],
"clients":
[
],
"dbid": 76864576,
"version": 1,
"id": "dbpack21"
}
首先我已经解析了对字符串的响应。
private static String getContent(HttpResponse response) {
HttpEntity entity = response.getEntity();
if (entity == null) return null;
BufferedReader reader;
try {
reader = new BufferedReader(new InputStreamReader(entity.getContent()));
String line = reader.readLine();
reader.close();
return line;
} catch (IllegalStateException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
现在我正在尝试搜索特定项目,但我不知道如何继续。
String StringResponse = getContent(JsonResponse);
JSONObject jsonObject = new JSONObject(StringResponse);
JSONArray ProjectsArray= jsonObject.getJSONArray("projects");
这种做法是否正确?
最诚挚的问候!
答案 0 :(得分:0)
一旦你有阵列,尝试类似......
// Array to store the indexes of the JSONArray to remove
ArrayList<Integer> indexesToRemove = new ArrayList<Integer>();
// Iterate through projects array, check the object at each position
// if it contains the string you want, add its index to the removal list
for (int i = 0; i < projectsArray.length; i++) {
JSONObject current = projectsArray.get(i);
if (current.get("projectKey") == "**DESIRED PROJECT KEY**") {
indexesToRemove.add(i);
}
}
现在,您可以遍历索引以删除,并使用JSONArrays remove方法从数组中删除相应的对象(不确定它的名称,上面的代码来自内存)。确保删除项目BACKWARDS,否则您将删除先前的项目,这将更改索引,导致您删除不正确的项目,如果您删除另一个索引。
// Going through the list backwards so we can remove the highest item each
//time without affecting the lower items
for (int i = indexesToRemove.size()-1; i>=0; i--) {
projectsArray.remove(indexesToRemove.get(i));
}