这个查询需要大约2分钟才能执行(更改9条记录):
UPDATE table1 t1
SET t1.code_id = null, t1.code_group = null
WHERE t1.another_id IN (SELECT t2.another_id
FROM table2 t2
WHERE ((t2.id_parent = 2658 AND t2.year = 2016)
OR (t2.id = 2658 AND t2.year = 2016)))
单独执行此查询需要0.0030秒:
SELECT t2.another_id
FROM table2 t2
WHERE ((t2.id_parent = 2658 AND t2.year = 2016)
OR (t2.id = 2658 AND t2.year = 2016))
并以整数形式返回3行。
以下是两个表的信息:
CREATE TABLE IF NOT EXISTS `table1`
(
`another_id` int(11) NOT NULL,
`table1_id` int(11) NOT NULL,
`code_group` varchar(1) DEFAULT NULL,
`code_id` int(10) DEFAULT NULL,
PRIMARY KEY (`another_id`,`table1_id`),
KEY `another_id` (`another_id`),
KEY `code_group` (`code_group`,`code_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
CREATE TABLE IF NOT EXISTS `table2`
(
`id_year` int(11) NOT NULL,
`id` int(11) NOT NULL,
`id_parent` int(11) DEFAULT NULL,
`another_id` int(11) NOT NULL,
`code_group` varchar(1) DEFAULT NULL,
`code_id` int(10) DEFAULT NULL,
PRIMARY KEY (`id_year`,`id`),
KEY `id_parent` (`id_year`,`id_parent`)
KEY `another_id` (`another_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_polish_ci;
有谁可以告诉我为什么需要2分钟才能执行此查询?
答案 0 :(得分:1)
您可以使用INNER JOIN更新如下:t2.year也不存在
UPDATE table1 t1
INNER JOIN table2 t2 ON t2.another_id = t1.another_id
AND ((t2.id_parent= 2658 AND t2.year= 2016) OR (t2.id= 2658 AND t2.year= 2016))
SET t1.code_id = NULL, t1.code_group = NULL
答案 1 :(得分:1)
IN
有时会妨碍优化。我首先将子查询直接放在FROM
子句中:
UPDATE table1 t1 JOIN
(SELECT t2.another_id
FROM table2 t2
WHERE ((t2.id_parent= 2658 AND t2.year= 2016) OR
(t2.id= 2658 AND t2.year= 2016)
)
) t2
ON t1.another_id = t2.another_id
SET t1.code_id = null,
t1.code_group = null;
然后,看一下这个查询,我建议在table1(another_id)
上建一个索引。实际上,该索引可能足以满足您的原始查询。