Question

firstName = ['abcd','efghi','jkl','mnopqr']
lastName  = ['xyz','pqrst','uvw','klmn']

我想要的输出是

abcd xyz a.xyz@example.com
efghi pqrst e.pqrst@example.com 
jkl uvw j.uvw@example.com 
mnopqr klmn m.klmn@example.com

我尝试了各种各样的方法并且失败了。我能想出的最接近的是

for x,y in zip(firstName,lastName):
    print(x,y)

我该怎么办？

Answer 1

使用基本字符串格式并打印输出，如下所示：

for x, y in zip(firstName,lastName):
    print(x, y, "%s.%s@example.com"%(x[0], y))

Answer 2

>>> for x,y in zip(firstName,lastName):
...     print("{0}\t{1}\t{2}".format(x,y,x[0]+'.'+y+'@example.com'))
... 
abcd    xyz a.xyz@example.com
efghi   pqrst   e.pqrst@example.com
jkl uvw j.uvw@example.com
mnopqr  klmn    m.klmn@example.com

Answer 3

这将打印您正在寻找的输出。你真的只想打印吗？

<html ng-app="myApp" ...

Answer 4

firstName = ['abcd','efghi','jkl','mnopqr']
lastName  = ['xyz','pqrst','uvw','klmn']

for index in range(0, len(firstName)):

    first = firstName[index]
    last = lastName[index]
    email = first[0] + '.' + last + '@example.com'

    print first, last, email

Answer 5

for i,j in zip(firstName,lastName):
    print (i+" "+j+" "+i[0]+"."+j+"@example.com")

输出

abcd xyz a.xyz@example.com
efghi pqrst e.pqrst@example.com
jkl uvw j.uvw@example.com
mnopqr klmn m.klmn@example.com

假设我在python中有两个列表，包括名字列表和姓氏列表

5 个答案: