Question

我尝试只将.txt列表中的名字打印到新的文本文件中。

.txt列表看起来像这样（每对名称都在自己的行上，名称多于此处显示的名称）：

Smith, James
Doe, John
White, Susan

这是我目前的代码：

fname = input("Please enter the file name for your list of names: ")
infile = open(fname,"r")
data = infile.read()

outfile = open("student-firstnames.txt", "w")

first = data.split(",")[-1]
print(first, file=outfile)

print("First names have been written to student-firstnames.txt.")

这只给了我最后一个名字，但我想要一个只有名字的完整列表。我能做些什么来实现这个目标？

Answer 1

您可以尝试以下方法：

first = [i.split(", ")[1] for i in data.split("\n")]
print(first, file=outfile)

这会按换行符拆分数据，然后获取逗号之后的部分，这是第一个名称。

Answer 2

您可以迭代文件对象以一次处理一个文件的每一行：

with open(fname) as infile:
    for line in infile:
        ...

例如，您可以使用它来获取文件中每行的名字列表：

with open(fname) as infile:
    first_names = [line.strip('\n').split(', ')[1] for line in infile]

Answer 3

您也可以尝试将其命名为索引1。

fname = input("Please enter the file name for your list of names: ")
infile = open(fname,"r")
outfile = open("student-firstnames.txt", "w")
x = '\n,'.join([line.split(', ')[1].strip() for line in infile])
outfile.write(x)
outfile.close()
infile.close()

<强>输出：

James
,John
,Susan

Answer 4

在Python 3中你可以这样做：

fname = input("Please enter the file name for your list of names: ")

with open(fname, "r") as infile, open("student-firstnames.txt", "w") as outfile:
    for line in infile:
        firstname = line.strip().split(', ')[-1]
        print(firstname, file=outfile)

如何拆分名字和姓氏列表？

4 个答案: