所以分配指令就是这个
打印一组简单的说明,供用户选择 钥匙开门。
所以我认为实现这一目标的目标是。
制作库存[彩虹键]
打印清单(您有这些密钥)
要求猜猜钥匙会打开门
它将检查库存,如果它是红色键,它将打印"打开"
否则将打印继续猜测并从库存中删除密钥
这是我到目前为止所拥有的。我还没有弄清楚如何添加和检查库存。
keepGuess = True
correctKey = "red"
while keepGuess:
guess = raw_input("Guess the key to open the door: ")
if guess == correctKey:
print ("You may enter")
keepGuess = False
else:
print ("Keep guessing")
感谢您帮助我。 这是最终结果
keepGuess = True
correctKey = "blue"
keys = ["red", "orange", "yellow", "green", "blue", "indigo", "violet"]
print keys
print
while keepGuess:
guess = raw_input("Which key will open the door? ")
if guess == correctKey:
print ("You may enter")
keepGuess = False
else:
if guess in keys != "blue":
keys.remove(guess)
if guess not in keys:
print
print ("The key didn't open the door.")
print ("Keep guessing")
print
print keys
print
打印出来
['red', 'orange', 'yellow', 'green', 'blue', 'indigo', 'violet']
Which key will open the door? red
The key didn't open the door.
Keep guessing
['orange', 'yellow', 'green', 'blue', 'indigo', 'violet']
Which key will open the door? red
Which key will open the door? blue
You may enter
答案 0 :(得分:0)
如果没有关于错误检查的更多信息,我无法确定我是否正在解决问题。但是,我认为您想要维护一个简单的键列表,例如:
door_key_inv = ["red", "yellow", "paisley-print chartreuse"]
您将列表作为 [] (即为空)启动,并在找到密钥时添加。
现在,当用户输入猜测时,您必须进行两次检查:
这是库存中的关键颜色吗?如果是,请转到步骤2;如果没有,请打印警告。
如果在door_key_inv中猜测:
这是正确的密钥吗?如果是这样,打开门并打破循环
这就是你需要的吗?
答案 1 :(得分:0)
你非常接近。您只需初始化一个空列表即可存储库存。当有人猜到一个键时,你只需将它附加到列表中即可。当然,我们会检查猜测的密钥是否已经存在于清单中,如果是,我们将不会添加它。
keepGuess = True
correctKey = "red"
inventory = []
while keepGuess:
guess = raw_input("Guess the key to open the door: ")
if guess == correctKey:
print ("You may enter")
inventory.append(guess)
keepGuess = False
else:
if guess not in inventory:
inventory.append(guess)
else:
print ("You have already added this key to your inventory.")
print ("Keep guessing")
这是一个测试:
Guess the key to open the door: blue
Keep guessing
Guess the key to open the door: blue
You have already added this key to your inventory.
Keep guessing
Guess the key to open the door: red
You may enter