Question

我的Impala查询中出现以下错误：

select 
   upload_key, 
   max(my_timestamp) as upload_time, 
   max(color_key) as max_color_fk, 
   count(distinct color_key) as color_count, 
   count(distinct id) as toy_count 
from upload_table 
group by upload_key

并收到错误：

AnalysisException：所有DISTINCT聚合函数都需要具有与count相同的参数集（DISTINCT color_key）;偏离 function：count（DISTINCT id）

我不确定为什么会收到此错误。我所做的是为每个小组（按upload_key分组），我尝试计算了多少distinct id以及多少distinct color_key。
有没有人有任何想法

Answer 1

错误消息表明DISTINCT仅允许在一个列[组合] 上，但您尝试两个color_key＆amp; id。解决方法是两个选择，然后是连接：

select
   t1.upload_key,
   t1.upload_time,
   t1.max_color_fk,
   t1.color_count,
   t2.toy_count
from
 (
   select 
      upload_key, 
      max(my_timestamp) as upload_time, 
      max(color_key) as max_color_fk, 
      count(distinct color_key) as color_count
   from upload_table 
   group by upload_key
 ) as t1
join
 (
   select 
      upload_key
      count(distinct id) as toy_count 
   from upload_table 
   group by upload_key
 ) as t2
on t1. upload_key = t2.upload_key

Impala：所有DISTINCT聚合函数都需要具有相同的参数集

1 个答案: