我在R
w / autoplot
中看到了这个教程。他们绘制了负载和加载标签:
autoplot(prcomp(df), data = iris, colour = 'Species',
loadings = TRUE, loadings.colour = 'blue',
loadings.label = TRUE, loadings.label.size = 3)
https://cran.r-project.org/web/packages/ggfortify/vignettes/plot_pca.html
我更喜欢Python 3
w / matplotlib, scikit-learn, and pandas
进行数据分析。但是,我不知道如何添加这些?
如何使用matplotlib
?
我一直在阅读Recovering features names of explained_variance_ratio_ in PCA with sklearn,但还没有想出来
以下是我在Python
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
from sklearn.datasets import load_iris
from sklearn.preprocessing import StandardScaler
from sklearn import decomposition
import seaborn as sns; sns.set_style("whitegrid", {'axes.grid' : False})
%matplotlib inline
np.random.seed(0)
# Iris dataset
DF_data = pd.DataFrame(load_iris().data,
index = ["iris_%d" % i for i in range(load_iris().data.shape[0])],
columns = load_iris().feature_names)
Se_targets = pd.Series(load_iris().target,
index = ["iris_%d" % i for i in range(load_iris().data.shape[0])],
name = "Species")
# Scaling mean = 0, var = 1
DF_standard = pd.DataFrame(StandardScaler().fit_transform(DF_data),
index = DF_data.index,
columns = DF_data.columns)
# Sklearn for Principal Componenet Analysis
# Dims
m = DF_standard.shape[1]
K = 2
# PCA (How I tend to set it up)
Mod_PCA = decomposition.PCA(n_components=m)
DF_PCA = pd.DataFrame(Mod_PCA.fit_transform(DF_standard),
columns=["PC%d" % k for k in range(1,m + 1)]).iloc[:,:K]
# Color classes
color_list = [{0:"r",1:"g",2:"b"}[x] for x in Se_targets]
fig, ax = plt.subplots()
ax.scatter(x=DF_PCA["PC1"], y=DF_PCA["PC2"], color=color_list)
答案 0 :(得分:13)
biplot
函数执行以下操作。在这个例子中,我使用的是虹膜数据:import numpy as np
import matplotlib.pyplot as plt
from sklearn import datasets
from sklearn.decomposition import PCA
import pandas as pd
from sklearn.preprocessing import StandardScaler
iris = datasets.load_iris()
X = iris.data
y = iris.target
#In general a good idea is to scale the data
scaler = StandardScaler()
scaler.fit(X)
X=scaler.transform(X)
pca = PCA()
x_new = pca.fit_transform(X)
def myplot(score,coeff,labels=None):
xs = score[:,0]
ys = score[:,1]
n = coeff.shape[0]
scalex = 1.0/(xs.max() - xs.min())
scaley = 1.0/(ys.max() - ys.min())
plt.scatter(xs * scalex,ys * scaley, c = y)
for i in range(n):
plt.arrow(0, 0, coeff[i,0], coeff[i,1],color = 'r',alpha = 0.5)
if labels is None:
plt.text(coeff[i,0]* 1.15, coeff[i,1] * 1.15, "Var"+str(i+1), color = 'g', ha = 'center', va = 'center')
else:
plt.text(coeff[i,0]* 1.15, coeff[i,1] * 1.15, labels[i], color = 'g', ha = 'center', va = 'center')
plt.xlim(-1,1)
plt.ylim(-1,1)
plt.xlabel("PC{}".format(1))
plt.ylabel("PC{}".format(2))
plt.grid()
#Call the function. Use only the 2 PCs.
myplot(x_new[:,0:2],np.transpose(pca.components_[0:2, :]))
plt.show()
<强> RESULT 强>
答案 1 :(得分:6)
尝试使用“ pca”库。这将绘制解释的方差,并创建一个双图。
pip install pca
from pca import pca
# Initialize to reduce the data up to the number of componentes that explains 95% of the variance.
model = pca(n_components=0.95)
# Or reduce the data towards 2 PCs
model = pca(n_components=2)
# Fit transform
results = model.fit_transform(X)
# Plot explained variance
fig, ax = model.plot()
# Scatter first 2 PCs
fig, ax = model.scatter()
# Make biplot with the number of features
fig, ax = model.biplot(n_feat=4)
答案 2 :(得分:1)
我在@teddyroland找到了答案:https://github.com/teddyroland/python-biplot/blob/master/biplot.py