我有以下查询(作为更大查询的一部分)。我试图从子查询中的2个不同的数据集中得到总和结果,但我无法将这两个数据封装成1个值。我有这个:
(Select SUM('Invoiced MTD') from
((Select SUM(CASE WHEN SOH.LASDLVNUM_0 <> '' AND SOH.LASINVNUM_0 <> '' AND MONTH(SOH.SHIDAT_0) = MONTH(GETDATE()) THEN
(SOP.NETPRI_0 * SOQ.QTY_0 * SOH.CHGRAT_0) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SORDER SOH
LEFT OUTER JOIN x3v6.CICPROD.BPCUSTOMER BPC on SOH.BPCORD_0 = BPC.BPCNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERQ SOQ on SOH.SOHNUM_0 = SOQ.SOHNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERP SOP on SOQ.SOHNUM_0 = SOP.SOHNUM_0 and SOQ.SOPLIN_0 = SOP.SOPLIN_0 and SOQ.SOQSEQ_0 = SOP.SOPSEQ_0
LEFT OUTER JOIN x3v6.CICPROD.ITMMASTER ITM on SOP.ITMREF_0 = ITM.ITMREF_0 ))
UNION ALL
((Select SUM(CASE WHEN SIH.INVTYP_0 = 2 and MONTH(SIH.ACCDAT_0) = MONTH(GETDATE()) THEN SID.AMTNOTLIN_0 * (-1) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SINVOICE SIH
Left Outer Join x3v6.CICPROD.SINVOICED SID on SIH.NUM_0 = SID.NUM_0))
as 'T2',
但是我收到UNION ALL条款的错误,我无法弄明白。基本上我想将销售贷项凭证与单独表格中的销售订单总金额合并。
有人可以帮助我吗?
答案 0 :(得分:0)
这有用吗?我不确定究竟是什么导致了你的问题,但你绝对不需要这么多括号。我还建议使用格式化/美化SQL的东西。这是1)保持代码看起来一致并且2)充实语法错误的好方法。
SELECT SUM(x.invoiced_mtd)
FROM (SELECT SUM(CASE
WHEN soh.lasdlvnum_0 <> '' AND soh.lasinvnum_0 <> '' AND
MONTH(soh.shidat_0) = MONTH(getdate()) THEN
(sop.netpri_0 * soq.qty_0 * soh.chgrat_0)
ELSE
0
END) AS invoiced_mtd
FROM x3v6.cicprod.sorder soh
LEFT OUTER JOIN x3v6.cicprod.bpcustomer bpc
ON soh.bpcord_0 = bpc.bpcnum_0
LEFT OUTER JOIN x3v6.cicprod.sorderq soq
ON soh.sohnum_0 = soq.sohnum_0
LEFT OUTER JOIN x3v6.cicprod.sorderp sop
ON soq.sohnum_0 = sop.sohnum_0
AND soq.soplin_0 = sop.soplin_0
AND soq.soqseq_0 = sop.sopseq_0
LEFT OUTER JOIN x3v6.cicprod.itmmaster itm
ON sop.itmref_0 = itm.itmref_0
UNION ALL
SELECT SUM(CASE
WHEN sih.invtyp_0 = 2 AND
MONTH(sih.accdat_0) = MONTH(getdate()) THEN
sid.amtnotlin_0 * (-1)
ELSE
0
END)
FROM x3v6.cicprod.sinvoice sih
LEFT OUTER JOIN x3v6.cicprod.sinvoiced sid
ON sih.num_0 = sid.num_0) x;
答案 1 :(得分:0)
这个怎么样?
Select SUM([Invoiced MTD]) from
(
Select SUM(CASE WHEN SOH.LASDLVNUM_0 <> '' AND SOH.LASINVNUM_0 <> '' AND MONTH(SOH.SHIDAT_0) = MONTH(GETDATE())
THEN (SOP.NETPRI_0 * SOQ.QTY_0 * SOH.CHGRAT_0) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SORDER SOH
LEFT OUTER JOIN x3v6.CICPROD.BPCUSTOMER BPC on SOH.BPCORD_0 = BPC.BPCNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERQ SOQ on SOH.SOHNUM_0 = SOQ.SOHNUM_0
LEFT OUTER JOIN x3v6.CICPROD.SORDERP SOP on SOQ.SOHNUM_0 = SOP.SOHNUM_0 and SOQ.SOPLIN_0 = SOP.SOPLIN_0 and SOQ.SOQSEQ_0 = SOP.SOPSEQ_0
LEFT OUTER JOIN x3v6.CICPROD.ITMMASTER ITM on SOP.ITMREF_0 = ITM.ITMREF_0
UNION ALL
Select SUM(CASE WHEN SIH.INVTYP_0 = 2 and MONTH(SIH.ACCDAT_0) = MONTH(GETDATE())
THEN SID.AMTNOTLIN_0 * (-1) ELSE 0 END) as 'Invoiced MTD'
From x3v6.CICPROD.SINVOICE SIH
Left Outer Join x3v6.CICPROD.SINVOICED SID on SIH.NUM_0 = SID.NUM_0
)T
答案 2 :(得分:0)
首先尝试使用CTE进行UNION
查询。以下是与查询结构相同的简化示例:
;with cteTest AS (
((select 2 as 'test'))
union all
((select 3 as 'test'))
)
select sum(test) from cteTest