Question

我有下面的查询，我想要总结，在这一刻，我得到两行，每个查询的每个总和一个，无论如何都要添加两个总和所以返回总和的一行两个查询？提前谢谢

 SELECT count(*)

    FROM
      eUser  eUser2 RIGHT OUTER JOIN prcIncidentManagement ON (eUser2.eUserName=prcIncidentManagement.AssignedTo)
       INNER JOIN eFolder ON (prcIncidentManagement.EFOLDERID=eFolder.eFolderID)
    WHERE
     eFolder.eCreationTime  between '01/01/2015'  and '13/10/2015'
    union
    SELECT count(*)
    FROM
      eUser RIGHT OUTER JOIN prcRequestFulfilment ON (prcRequestFulfilment.AssignedTo=eUser.eUserName)
       INNER JOIN eFolder ON (eFolder.eFolderID=prcRequestFulfilment.EFOLDERID)
    WHERE
     eFolder.eCreationTime  between '01/01/2015'  and '13/10/2015'

Answer 1

除非我建议您使用UNION ALL代替UNION，否则我们应该为您执行此操作。

如果您的两个查询都返回相同的值，则UNION运算符会在两个值之间生成隐式DISTINCT，而您的SUM只会是其中一个值，而不是被加倍。

SELECT SUM(cnt_val) Sum_Values
FROM (
    SELECT count(*) cnt_val
    FROM eUser eUser2
    RIGHT JOIN prcIncidentManagement
        ON (eUser2.eUserName = prcIncidentManagement.AssignedTo)
    INNER JOIN eFolder
        ON (prcIncidentManagement.EFOLDERID = eFolder.eFolderID)
    WHERE eFolder.eCreationTime BETWEEN '01/01/2015'
            AND '13/10/2015'

    UNION ALL

    SELECT count(*) cnt_val
    FROM eUser
    RIGHT JOIN prcRequestFulfilment
        ON (prcRequestFulfilment.AssignedTo = eUser.eUserName)
    INNER JOIN eFolder
        ON (eFolder.eFolderID = prcRequestFulfilment.EFOLDERID)
    WHERE eFolder.eCreationTime BETWEEN '01/01/2015'
            AND '13/10/2015'
    ) Result_Set

因此，假设两个查询的结果是：

2 --> first query result
2 --> second query result

如果您使用UNION代替UNION ALL，则总和将为2。

Answer 2

这应该有效 -

SELECT SUM(Cnt) FROM
    (SELECT count(*) AS Cnt

        FROM
          eUser  eUser2 RIGHT OUTER JOIN prcIncidentManagement ON (eUser2.eUserName=prcIncidentManagement.AssignedTo)
           INNER JOIN eFolder ON (prcIncidentManagement.EFOLDERID=eFolder.eFolderID)
        WHERE
         eFolder.eCreationTime  between '01/01/2015'  and '13/10/2015'
        union
        SELECT count(*)
        FROM
          eUser RIGHT OUTER JOIN prcRequestFulfilment ON (prcRequestFulfilment.AssignedTo=eUser.eUserName)
           INNER JOIN eFolder ON (eFolder.eFolderID=prcRequestFulfilment.EFOLDERID)
        WHERE
         eFolder.eCreationTime  between '01/01/2015'  and '13/10/2015') A

Answer 3

尝试：

select sum(cnt) total_cnt
from (
    SELECT count(*) cnt
    FROM eUser  eUser2 
    RIGHT OUTER JOIN prcIncidentManagement ON eUser2.eUserName = prcIncidentManagement.AssignedTo
    INNER JOIN eFolder ON prcIncidentManagement.EFOLDERID = eFolder.eFolderID
    WHERE eFolder.eCreationTime  between '01/01/2015'  and '10/13/2015'

    union all

    SELECT count(*)
    FROM eUser 
    RIGHT OUTER JOIN prcRequestFulfilment ON prcRequestFulfilment.AssignedTo = eUser.eUserName
    INNER JOIN eFolder ON eFolder.eFolderID = prcRequestFulfilment.EFOLDERID
    WHERE eFolder.eCreationTime  between '01/01/2015'  and '10/13/2015'
) x

您可以使用union all代替union 如果您使用union并且第一个和第二个查询返回的count相同，则union将删除一个计数，因为它只允许不同的值。
所以，你不会得到你期望的结果。

日期必须采用mm/dd/yyyy格式，否则请使用convert从字符串中获取数据。

Answer 4

嗯，你可以取两个输出然后总和。无需使用Union all或Union。

Declare @SumOfIncident int= (SELECT count(*)

FROM eUser eUser2 RIGHT OUTER JOIN prcIncidentManagement ON (eUser2.eUserName=prcIncidentManagement.AssignedTo) INNER JOIN eFolder ON (prcIncidentManagement.EFOLDERID=eFolder.eFolderID)

WHERE eFolder.eCreationTime between '01/01/2015' and '13/10/2015' )


Declare @requestOfFullfillment int= (SELECT count(*)

FROM eUser eUser2 RIGHT OUTER JOIN prcIncidentManagement ON (eUser2.eUserName=prcIncidentManagement.AssignedTo) INNER JOIN eFolder ON (prcIncidentManagement.EFOLDERID=eFolder.eFolderID)

WHERE eFolder.eCreationTime between '01/01/2015' and '13/10/2015' )

SELECT @SumOfIncident   + @requestOfFullfillment

将两个SQL查询合并为一个

4 个答案: