Question

我正在尝试在C中创建一个简单的链接列表。但程序只是跳过＆＃34; 输入更多节点？[y / n] ＆＃34;部分。这是我的计划：

#include<stdio.h>
#include<stdlib.h>

struct node{
    int data;
    struct node *next;
}*start = NULL;

void createlist()
{
    int item;
    char choice = 'y';

    struct node *newNode;
    struct node *current;

    while(choice != 'n')
    {
        printf("Enter item to add in the Linked List\n\n");
        scanf("%d", &item);

        newNode = (struct node *)malloc(sizeof(struct node));

        newNode->data = item;
        newNode->next = NULL;

        if(start == NULL)
        {
            start = newNode;
            current = newNode;
        }
        else
        {
            current->next = newNode;
            current = newNode;
        }

        printf("Enter more nodes?[y/n]\n");
        scanf("%c", &choice);
    }
}

void display()
{
    struct node *new_node;
    printf("Your node is :\n");
    new_node = start;
    while(new_node!=NULL)
    {
        printf("%d ---> ", new_node->data );
        new_node = new_node->next;

    }
}

int main()
{
    createlist();
    display();
    return 0;
}

输出： Program skipping choice input part

但是当我从 char 更改选择变量 int 时，程序运行完美。这是工作职能：

void createlist()
{
    int item;
    int choice = 1;

    struct node *newNode;
    struct node *current;

    while(choice != 0)
    {
        printf("Enter item to add in the Linked List\n\n");
        scanf("%d", &item);

        newNode = (struct node *)malloc(sizeof(struct node));

        newNode->data = item;
        newNode->next = NULL;

        if(start == NULL)
        {
            start = newNode;
            current = newNode;
        }
        else
        {
            current->next = newNode;
            current = newNode;
        }

        printf("Enter more nodes?\n[NO - 0, YES - 1]\n");
        scanf("%d", &choice);
    }
}

当选择是 char 类型时，你能告诉我为什么程序工作不正常吗？

Answer 1

输入缓冲区中剩余newline，正在为%c格式读取。变化

scanf("%c", &choice);

到

scanf(" %c", &choice);`

前导空格告诉scanf先清除空白。这会自动以%d格式发生。

在链接列表

1 个答案: