在BufferedImage中绘制多条线

时间:2010-10-12 11:45:08

标签: java swing drawing lines bufferedimage

我正在尝试在bufferedimage上绘制水平和垂直线条。它应该看起来像一个细胞网格。但是当我运行代码时,我只看到两行:最左边的行和最上面的行(即从0,0到0的行,图像的高度和0,0到图像的宽度,0)继承代码片段:

  BufferedImage mazeImage = new BufferedImage(imgDim.width, imgDim.height, BufferedImage.TYPE_INT_RGB);
  Graphics2D g2d = mazeImage.createGraphics();
  g2d.setBackground(Color.WHITE);
  g2d.fillRect(0, 0, imgDim.width, imgDim.height);
  g2d.setColor(Color.BLACK);
  BasicStroke bs = new BasicStroke(2);
  g2d.setStroke(bs);
  // draw the black vertical and horizontal lines
  for(int i=0;i<21;i++){
   g2d.drawLine((imgDim.width+2)*i, 0, (imgDim.width+2)*i,  imgDim.height-1);
   g2d.drawLine(0, (imgDim.height+2)*i, imgDim.width-1, (imgDim.height+2)*i);
  }

覆盖绘画方法:

public void paint(Graphics g) {
  g.drawImage(mazeImage, 0, 0, this);
}

这是一个名为RobotMaze的类,它扩展了JPanel。任何帮助表示赞赏。

3 个答案:

答案 0 :(得分:8)

import java.awt.*;
import java.awt.image.*;
import javax.swing.*;

class GridLines {

    public static void main(String[] args) {

        Dimension imgDim = new Dimension(200,200);
        BufferedImage mazeImage = new BufferedImage(imgDim.width, imgDim.height, BufferedImage.TYPE_INT_RGB);


        Graphics2D g2d = mazeImage.createGraphics();
        g2d.setBackground(Color.WHITE);
        g2d.fillRect(0, 0, imgDim.width, imgDim.height);
        g2d.setColor(Color.BLACK);
        BasicStroke bs = new BasicStroke(2);
        g2d.setStroke(bs);
        // draw the black vertical and horizontal lines
        for(int i=0;i<21;i++){
            // unless divided by some factor, these lines were being
            // drawn outside the bound of the image..
            g2d.drawLine((imgDim.width+2)/20*i, 0, (imgDim.width+2)/20*i,imgDim.height-1);
            g2d.drawLine(0, (imgDim.height+2)/20*i, imgDim.width-1, (imgDim.height+2)/20*i);
        }

        ImageIcon ii = new ImageIcon(mazeImage);
        JOptionPane.showMessageDialog(null, ii);
    }
}

答案 1 :(得分:1)

打印出你的坐标,你会发现你正在绘制超出图像宽度和高度的点:

System.out.printf("Vertical: (%d,%d)->(%d,%d)\n",(imgDim.width+2)*i, 0, (imgDim.width+2)*i,  imgDim.height-1);
System.out.printf("Horizontal: (%d,%d)->(%d,%d)\n",0, (imgDim.height+2)*i, imgDim.width-1, (imgDim.height+2)*i);

答案 2 :(得分:0)

如果我&gt;你如何期望(imgDim.width+2)*i的结果在图像边界内? 0?