无法更新onTouch事件中的新位置

时间:2016-08-24 15:28:55

标签: java android layout ontouch

我是初学者,但我想制作一款游戏。现在我正在为我的英雄做移动功能。当我触摸图像并将其移动到右侧时,英雄将从原始位置向右移动每秒100dp,但它无法工作。

以下是我用作移动功能的代码:

public View.OnTouchListener move = new View.OnTouchListener() {
    private float x, y;
    private int mx, my, hx, hy;

    public boolean onTouch(final View v, MotionEvent event) {
        if ((event.getAction() == MotionEvent.ACTION_DOWN)) {

            x = event.getX();
            y = event.getY();
            mx = (int) (event.getRawX() - x);
            my = (int) (event.getRawY() - y);

        } else if ((event.getAction() == MotionEvent.ACTION_MOVE)) {

            hx = (int) (event.getRawX() - x);
            hy = (int) (event.getRawY() - y);
            v.layout(hx, hy, hx + v.getWidth(), hy + v.getHeight());

        } else if ((event.getAction() == MotionEvent.ACTION_UP)) {

            while (hx > mx) {
                final Handler handler = new Handler();
                handler.postDelayed(new Runnable() {
                    @Override
                    public void run() {
                        mx += 100;
                        v.layout(mx, my, mx + v.getWidth(), my + v.getHeight());
                    }
                }, 1000);
            }
        }
        Log.e("x =", String.valueOf(x) + "    y =" + String.valueOf(y));
        Log.e("hx =", String.valueOf(hx) + "    hy =" + String.valueOf(hy));
        Log.e("mx =", String.valueOf(mx) + "    my =" + String.valueOf(my)); 
        return true;
    }
};

1 个答案:

答案 0 :(得分:0)

ACTION_MOVEACTION_UP

中执行此操作
RelativeLayout.LayoutParams layoutParams = (RelativeLayout.LayoutParams) view.getLayoutParams();

//edit layout params according to your need
view.setLayoutParams(layoutParams);