我需要丢弃几个月的日子，并将重复的月份区分开来

Question

SELECT  e.firstName,t.setDate, w.wageAmount
         FROM TimeSheet t
         INNER JOIN Employee e
         ON e.employeeID = t.employeeID
         INNER JOIN Salary s
         ON s.salaryID = t.salaryID
         INNER JOIN Wage w
         ON w.wageID = s.wageID
         INNER JOIN EmpHiringInfo ehf
         ON ehf.EmpHiringInfoID = s.EmpHiringInfoID
         INNER JOIN WageType wt
         ON wt.wageTypeID = w.wageTypeID
         WHERE (wt.wageTypeID = 19) AND (ehf.isActive = 1 AND s.isActive = 1
         AND ehf.employeeID = 300) AND (CONVERT(varchar, t.setDate, 23) BETWEEN '2000-08-02' AND '2020-08-04')

顺便说一下，工资每个月只有一个，所以工资是重复的。所以对于2010年11月，无论11,2010多少天，工资是3600 ......

以上示例生成以下示例代码：

我需要将所有类似的月/年收集到一个单元格中，丢弃日期和时间。例如 2010-11-12和2010-11-26必须按照2010-11（任何格式）签约一个单元格。

感谢任何帮助。

Answer 1

要将所有日期统一到几个月，您可以执行以下操作：

dateadd(mm,datediff(mm,0,t.setDate),0)

但是你需要分组才能进行聚合：

select e.firstName,dateadd(mm,datediff(mm,0,t.setDate),0), sum(w.wageAmount)
from ...
group by e.firstName, dateadd(mm,datediff(mm,0,t.setDate),0)

Answer 2

您可以尝试以下内容：

SELECT  e.firstName
,CONVERT(CHAR(7),t.setDate,102)
,SUM(w.wageAmount)
FROM ...

GROUP BY e.firstName, 
,CONVERT(CHAR(7),t.setDate,102)

Answer 3

T-SQL中有DatePart function能够检索特定日期的日期和年份。

您的查询可能如下所示：

SELECT  e.firstName, 
DATEPART(yy, t.setDate) AS Year, 
DATEPART(mm, t.setDate) AS Month, 
MAX(w.wageAmount) AS wageAmount
FROM TimeSheet t
     INNER JOIN Employee e
     ON e.employeeID = t.employeeID
     INNER JOIN Salary s
     ON s.salaryID = t.salaryID
     INNER JOIN Wage w
     ON w.wageID = s.wageID
     INNER JOIN EmpHiringInfo ehf
     ON ehf.EmpHiringInfoID = s.EmpHiringInfoID
     INNER JOIN WageType wt
     ON wt.wageTypeID = w.wageTypeID
     WHERE (wt.wageTypeID = 19) AND (ehf.isActive = 1 AND s.isActive = 1
     AND ehf.employeeID = 300) AND 
     (CONVERT(varchar, t.setDate, 23) BETWEEN '2000-08-02' AND '2020-08-04')
GROUP BY e.firstName, DATEPART(yy, t.setDate), DATEPART(mm, t.setDate)