找到月份差异，然后在几个月后剩下几天 - mysql

Question

我需要找到两个日期之间的差异，根据结果进行一些计算。

让我们说列start_date的值为1 / Jan / 2014，列end_date的值为15 / Mar / 2014。我想要的结果是以下格式：

months | days_remain |
----------------------
   2          15

我可以使用MONTH函数分别找到DAY差异和TIMESTAMPDIFF之间的差异（2个月和74天）。但如何找出剩余的15天？

Answer 1

我认为这可能就是你想要的。然而，它确实会剩下14天，但正如Jaugar Chang在评论中指出的那样，如果3月1日到3月15日之间的差异是14天那么应该是正确的。

select
  timestampdiff(
    month, 
    start_date, 
    end_date
  ) as months,
  datediff(
    end_date,
    timestampadd(
      month, 
      timestampdiff(
        month, 
        start_date, 
        end_date
      )
      ,start_date
    )     
  ) as days_remain

from test;

Sample SQL Fiddle

示例结果：

|       START_DATE |       END_DATE | MONTHS | DAYS_REMAIN |
|------------------|----------------|--------|-------------|
| January, 01 2014 | March, 15 2014 |      2 |          14 |
| January, 10 2014 | March, 13 2014 |      2 |           3 |

Answer 2

您可以使用DATEDIFF查看2个日期之间的差异

SELECT DATEDIFF('2006-04-01','2005-04-01');

http://lists.mysql.com/mysql/196414

Answer 3

试试这个，我希望它能为你效劳。

select DateDiff(d, datepart(month,[Start_Date]),datepart(month,End_Date)) as  Months,

(30-day(end_date)) as Days_remain

from Sdate 

Answer 4

这肯定会有效。

Declare @StartDate datetime
Declare @EndDate datetime
Declare @years varchar(40)
Declare @months varchar(30)
Declare @days varchar(30)

set @StartDate ='2014/01/01'
set @EndDate = '2014/03/15'
select @years=datediff(year,@StartDate,@EndDate)
select @months=datediff(month,@StartDate,@EndDate)-(datediff(year,@StartDate,@EndDate)*12)
select @days=datepart(d,@EndDate)-datepart(d,@StartDate)
select @years  +' years,   ' +@months +' months,   '+@days   +' days' asYearMonthDay 

Answer 5

试试这个。请参阅示例数据：

select 
  dt1, dt2,
  trunc( months_between(dt2,dt1) ) mths, 
  dt2 - add_months( dt1, trunc(months_between(dt2,dt1)) ) days
from
(
    select date '2012-01-01' dt1, date '2012-03-25' dt2 from dual union all
    select date '2012-01-01' dt1, date '2013-01-01' dt2 from dual union all
    select date '2012-01-01' dt1, date '2012-01-01' dt2 from dual union all
    select date '2012-02-28' dt1, date '2012-03-01' dt2 from dual union all
    select date '2013-02-28' dt1, date '2013-03-01' dt2 from dual union all
    select date '2013-02-28' dt1, date '2013-04-01' dt2 from dual 
) sample_data;

希望它有所帮助。