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我错过了什么?为什么dd = data.table(a = c(1,1), b = c(1,2), v = c(1, NA))
dd
# a b v
# 1: 1 1 1
# 2: 1 2 NA
setkey(dd, a,b)
dd[.(1,2), roll = TRUE, rollends = c(TRUE, TRUE)]
# a b v
# 1: 1 2 NA
没有结转?
答案 0 :(得分:2)
滚动连接不需要在此处滚动,因为您匹配确切的行(1, 2)
。当实际值不匹配时进行滚动匹配,在您的情况下,它具有完全匹配。请参阅以下示例,我修改了dd
,因此.(1,2)
上没有匹配。
library(data.table)
dd = data.table(a = c(1,1), b = c(1,3), v = c(1, NA))
dd[.(1,2), roll = TRUE, rollends = c(TRUE, TRUE)]
# a b v
#1: 1 2 1
请参阅?data.table
// roll
(强调我的):
当
i
为data.table
且其行与匹配除最后一个x
加入列以外的所有内容时,以及其在i
中的值}连接列落在一个间隙中(包括在该组的x
中的最后一次观察之后),然后:
+Inf
(或TRUE
)在x
向前滚动盛行值。它也被称为最后一次观察(LOCF)...