Question

例如

<div ng-repeat = 'list in lists'>

<?php 

 $user_post_id = "{{list.user.id}}";          //this syntax works
 var_dump($user_post_id);                     // gives String(16) '1'     
 $user_post_int_id = (int)$user_post_id;      // change from string to int
 var_dump($user_post_int_id);                 // gives int(1) 0, I don't know why isn't type conversion working!

 echo $user_post_id;                         // echoes out 1
 echo $user_post_int_id;                     //echoes out the 0

所以我认为主要的问题是类型转换，因为我尝试了另外一件事，其中String（1）转换为int（1）没有问题，但是使用字符串（16），所有东西都分开并导致结果为0。 / p>

Answer 1

您不能在服务器端语句中使用Angular表达式，因为Angular语句在运行所有服务器逻辑后在客户端运行。

在您的代码中：

<div ng-repeat = 'list in lists'>

<?php 

 $user_post_id = "{{list.user.id}}"          //list.user.id is a JS variable, you cannot use it in PHP.
 $user_post_int_id = (int)$user_post_id;     // something wrong here, you do not need this step, normally if you retrieved the code from server side.

 {{ $user_post_int_id }}                     //this should not work

But still this blade function fails

@if(Auth::user()->id == $user_post_int_id)
do something //returns false, makes alot of sense, as again you are trying to get variables from JS and passing them to PHP scripts. This will never work.
@endif

Answer 2

我有3个建议4u（在我的服务器上一切正常）

作为我的评论的原文：

<div ng-repeat = 'list in lists'>

<?php 

 $user_post_id = "{{list.user.id}}";          //this syntax works
 var_dump($user_post_id);                     // gives String(16) '1'     
 $user_post_int_id = (int)$user_post_id;      // change to int
 var_dump($user_post_int_id);                 
// gives int(1) 1, is not test your php/server conf!

 echo $user_post_id;                         // echoes out 1
 echo $user_post_int_id;                     //echoes out 1

然后我建议您尝试使用您的代码，在您的服务器上运行更改：

替换 $ user_post_id =“{{list.user.id}}”; 到 $ user_post_id =（int）{{list.user.id}}; //希望你的php不会显示错误
替换 $ user_post_int_id =（int）$ user_post_id; 到 $ user_post_int_id = floor（（int）$ user_post_id）; 或 $ user_post_int_id = ceil（（int）$ user_post_id）;
替换 $ user_post_id =“{{list.user.id}}”; 到 $ user_post_id =（int）（{{list.user.id}}）+ 1; 或者加零，这些黑客有时对我有用！

P.S。（int）可以对你做一个技巧，php可以说你使用了十六进制bin或其他。重新测试两次！ php.net/manual/en/language.types.integer.php php.net/manual/en/language.types.type-juggling.php

如何在php中将String（16）转换为Int（1）

2 个答案: