Question

我有一个json代码，尝试了很多方法但仍无法从json获取数据

JSON：

echo $answer->option; 
// will output    

{"customer_ans":["qqq","sss"],
    "show_image":["images/a.png","images/b.png"]},
    {"customer_ans":["ooo","ooo","ooo"],
    "show_image":["images/a.png","images/b.png","images/c.png"]}
    ...thesame...blablabla

当我尝试

时

foreach($answer->option as $mydata)

    {

         foreach($mydata->customer_ans as $values)
         {
              echo $values . "\n";
         }
    }

没有输出，我试过

$ansopts = json_decode( $answer->option,true );
for($i=0;$i<count($ansopts["customer_ans"]);$i++) {
    echo $ansopts["customer_ans"][$i];
}

仍然没有输出！

那么我怎样才能获得customer_ans值？

**********************************************更新*****************

for($i=0;$i<count($ansopts);$i++) {
    echo var_export( $ansopts["customer_ans"][$i]);
}

没有输出

echo '<pre>'.print_r(json_decode($answer->option, true), true).'</pre>';

无输出

var_dump函数：

var_dump($answer->option);
// will output
string(291) "{"customer_ans":["aaa","bbb"],"show_image":["images/a.png","images/a.png"]},{"customer_ans":["ccc","ddd","eee"],"show_image":["images/a.png","images/b.png","images/c.png"]}"

非常感谢大家！

Answer 1

以这种方式尝试：

#the json is a littel invalid to parse, missing [ ] around it 
$ansopts = json_decode('['.trim((string)$answer->option).']',true );

//test for errors
print json_last_error_msg ();
//to see it for real
var_export($ansopts);

//loop 
for($i=0;$i<count($ansopts);$i++) {
    echo $ansopts[$i]["customer_ans"][0];#qqq
    echo $ansopts[$i]["customer_ans"][1];#sss
}

Answer 2

尝试

$ansopts = json_decode( $answer->option,true );
foreach($ansopts as $mydata)
{
     foreach($mydata->customer_ans as $values)
     {
          echo $values . "\n";
     }
}

或者您可以尝试先转储变量

print_r($ansopts);exit;

奇怪的json foreach获得指定值

2 个答案: