Question

我需要从JSON文件创建一个c＃对象，并且必须遵循以下工作解决方案：

JSON：

{
"AK": {
    "Anchorage": [{
        "Name": "John Doe",
        "Address": "123 Main St.",
        "City": "Anchorage",
        "State": "AK",
        "Zip": "12345"
    }],
    "Fairbanks": [{
        "Name": "Sally Smith",
        "Address": "987 Main St.",
        "City": "Fairbanks",
        "State": "AK",
        "Zip": "98765"
    }]
}
}

代码：

public class Location
{
    public string Name { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    public string State { get; set; }
    public string Zip { get; set; }
}

// ------------------------------------------------------------------
string json = File.ReadAllText(@"C:json.txt");
dynamic deserialisedJson = JsonConvert.DeserializeObject(json);

var locations = new List<Location>();

foreach (var root in deserialisedJson)
{
    foreach (var state in root)
    {
        foreach (var city in state)
        {
            foreach (var location in city)
            {
                Location loc = new Location();
                loc.Name = location.First["Name"];
                loc.Address = location.First["Address"];
                loc.City = location.First["City"];
                loc.State = location.First["State"];
                loc.Zip = location.First["Zip"];
                locations.Add(loc);
            }
        }
    }
}

但我需要将上述内容整合到SSIS包中，该包仅允许使用.NET 3.5及更低版本。下面的代码行需要.NET 4.0及更高版本：

dynamic deserialisedJson = JsonConvert.DeserializeObject(json);

我试图通过使用IEnumerable来解决这个限制，但我不确定如何获取我需要的值的语法？

string json = File.ReadAllText(@"C:json.txt");

var deserialisedJson = (IEnumerable)JsonConvert.DeserializeObject(json);

var locations = new List<Location>();

foreach (var root in deserialisedJson)
{
    foreach (var state in (IEnumerable)root)
    {
        foreach (var city in (IEnumerable)state)
        {
            foreach (var location in (IEnumerable)city)
            {
                Location loc = new Location();

                loc.Name = //What goes here???
                loc.Address = //What goes here???
                loc.City = //What goes here???
                loc.State = //What goes here???
                loc.Zip = //What goes here???

                locations.Add(loc);
            }
        }
    }
}

Answer 1

这使用Linq to JSON来选择您想要的所有Location个对象：

var deserialisedJson = (IEnumerable)JsonConvert.DeserializeObject(json);
JObject jObj = JObject.Parse(json);

//Get all tokens that are under AK/(some descendant)/all items from collection
var result = jObj.SelectTokens("AK.*.[*]")
                    .Select(x => new Location
                    {
                        Name = x["Name"].Value<string>(),
                        Address = x["Address"].Value<string>(),
                        City = x["City"].Value<string>(),
                        State = x["State"].Value<string>(),
                        Zip = x["Zip"].Value<string>(),
                    }).ToList();

经过测试，这适用于.Net 3.5项目，其中Newtonsoft.Json包适用于.Net

Answer 2

这是一个快速解决方案：

>=

Answer 3

您可以使用clases让newtonsoft解决您需要的内容

public class Location
{
    public string Name { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    public string State { get; set; }
    public string Zip { get; set; }
}
public class AK
{
    public Location[] Anchorage { get; set; }
    public Location[] Fairbanks { get; set; }
}   


var ak = JsonConvert.DeserializeObject<AK>(json);

从IEnumerable foreach循环中获取价值

3 个答案: