Question

我有这个：

use [VERPLOEGEN-NAV2009-LIVE]
SELECT V.No_, VPL.[Location Code],V.Name, 
       SUM(VPL.Amount)  AS Total, 
       V.[Freight-free Limit]
     -- ISNULL(CAST( V.[Freight-free Limit] AS VARCHAR(10)), 'geen waarde')  
 FROM [Verploegen POC$Purch_ Inv_ Line] VPL
  JOIN [Verploegen POC$Vendor] V
     ON VPL.[Buy-from Vendor No_] = V.No_
--WHERE [Buy-from Vendor No_] =  '3929' -- is empty??' --'3932' --'3929' --'3923' --'3904' --'3885' --'3820' --'3894' 
WHERE VPL.[Buy-from Vendor No_] = '3929' 
      AND VPL.Type = 1  AND ([Posting Date] BETWEEN '2016-01-01' AND '2016-12-31') 
GROUP BY VPL.[Location Code], V.[Freight-free Limit], V.No_, V.Name  --, VPL.[Direct Unit Cost]
ORDER BY V.Name

并且有一个属性：VPL.Type = 1，但你与type=2具有相同的属性。但是在结果中我想要显示两个属性，使用type = 1和type =2。因为type = 1的总和不同，所以type = 2.的总和不同type = 1的结果是这样的：

3929    AM  ASF Fischer BV  20.89000000000000000000 350.00000000000000000000
3929    DB  ASF Fischer BV  -0.29000000000000000000 350.00000000000000000000
3929    DL  ASF Fischer BV  0.34000000000000000000  350.00000000000000000000
3929    RD  ASF Fischer BV  20.06000000000000000000 350.00000000000000000000
3929    ZM  ASF Fischer BV  0.04000000000000000000  350.00000000000000000000

那么如何使用type = 2创建一个额外的列？

谢谢

如果我这样做：

use [VERPLOEGEN-NAV2009-LIVE]
SELECT V.No_, VPL.[Location Code],V.Name, 
       SUM(VPL.Amount)  AS Total, 
       SUM(VPL.Amount) as total2,
       V.[Freight-free Limit]
     -- ISNULL(CAST( V.[Freight-free Limit] AS VARCHAR(10)), 'geen waarde')  
 FROM [Verploegen POC$Purch_ Inv_ Line] VPL 
  JOIN [Verploegen POC$Vendor] V
     ON VPL.[Buy-from Vendor No_] = V.No_
--WHERE [Buy-from Vendor No_] =  '3929' -- is empty??' --'3932' --'3929' --'3923' --'3904' --'3885' --'3820' --'3894' 
WHERE VPL.[Buy-from Vendor No_] = '3929' 
      AND VPL.Type = 1  AND ([Posting Date] BETWEEN '2016-01-01' AND '2016-12-31') 
GROUP BY VPL.[Location Code], V.[Freight-free Limit], V.No_, V.Name  --, VPL.[Direct Unit Cost]
ORDER BY V.Name

结果这个：

3929    AM  ASF Fischer BV  20.89000000000000000000 20.89000000000000000000 350.00000000000000000000
3929    DB  ASF Fischer BV  -0.29000000000000000000 -0.29000000000000000000 350.00000000000000000000
3929    DL  ASF Fischer BV  0.34000000000000000000  0.34000000000000000000  350.00000000000000000000
3929    RD  ASF Fischer BV  20.06000000000000000000 20.06000000000000000000 350.00000000000000000000
3929    ZM  ASF Fischer BV  0.04000000000000000000  0.04000000000000000000  350.00000000000000000000

但Total和Total2现在具有相同的值

你的意思是这样吗？

use [VERPLOEGEN-NAV2009-LIVE]
SELECT V.No_, VPL.[Location Code],V.Name,

       sum(case when Type =1 then 1 else 0 end )As type1sum,
        sum(case when Type =2 then 1 else 0 end )As type2sum,
       V.[Freight-free Limit]
     -- ISNULL(CAST( V.[Freight-free Limit] AS VARCHAR(10)), 'geen waarde')  
 FROM [Verploegen POC$Purch_ Inv_ Line] VPL 
  JOIN [Verploegen POC$Vendor] V
     ON VPL.[Buy-from Vendor No_] = V.No_
--WHERE [Buy-from Vendor No_] =  '3929' -- is empty??' --'3932' --'3929' --'3923' --'3904' --'3885' --'3820' --'3894' 
WHERE VPL.[Buy-from Vendor No_] = '3929' 
      AND  ([Posting Date] BETWEEN '2016-01-01' AND '2016-12-31') 
GROUP BY VPL.[Location Code], V.[Freight-free Limit], V.No_, V.Name  --, VPL.[Direct Unit Cost]
ORDER BY V.Name

输出：

3929    AM  ASF Fischer BV  4   39  350.00000000000000000000
3929    DB  ASF Fischer BV  4   67  350.00000000000000000000
3929    DL  ASF Fischer BV  8   128 350.00000000000000000000
3929    RD  ASF Fischer BV  4   36  350.00000000000000000000
3929    ZM  ASF Fischer BV  1   10  350.00000000000000000000

但是我必须把总和（金额）放在哪里？

Answer 1

从中删除Vpl.type并使用SUM与CASE ..

select 
 col1..
,sum(case when Type =1 then amount else 0 end )As type1sum,
 sum(case when Type =2 then amount else 0 end )As type2sum
from
table
grouping columns

显示与其他类型相同的列

1 个答案: