我正在为多个标记数据绘制混淆矩阵,其中标签看起来像:
label1:1,0,0,0
label2:0,1,0,0
label3:0,0,1,0
label4:0,0,0,1
我可以使用以下代码成功分类。 我只需要一些帮助来绘制混淆矩阵。
for i in range(4):
y_train= y[:,i]
print('Train subject %d, class %s' % (subject, cols[i]))
lr.fit(X_train[::sample,:],y_train[::sample])
pred[:,i] = lr.predict_proba(X_test)[:,1]
我使用以下代码打印混淆矩阵,但它总是返回2X2矩阵
prediction = lr.predict(X_train)
print(confusion_matrix(y_train, prediction))
答案 0 :(得分:2)
我找到了一个可以绘制从sklearn
生成的混淆矩阵的函数。
import numpy as np
def plot_confusion_matrix(cm,
target_names,
title='Confusion matrix',
cmap=None,
normalize=True):
"""
given a sklearn confusion matrix (cm), make a nice plot
Arguments
---------
cm: confusion matrix from sklearn.metrics.confusion_matrix
target_names: given classification classes such as [0, 1, 2]
the class names, for example: ['high', 'medium', 'low']
title: the text to display at the top of the matrix
cmap: the gradient of the values displayed from matplotlib.pyplot.cm
see http://matplotlib.org/examples/color/colormaps_reference.html
plt.get_cmap('jet') or plt.cm.Blues
normalize: If False, plot the raw numbers
If True, plot the proportions
Usage
-----
plot_confusion_matrix(cm = cm, # confusion matrix created by
# sklearn.metrics.confusion_matrix
normalize = True, # show proportions
target_names = y_labels_vals, # list of names of the classes
title = best_estimator_name) # title of graph
Citiation
---------
http://scikit-learn.org/stable/auto_examples/model_selection/plot_confusion_matrix.html
"""
import matplotlib.pyplot as plt
import numpy as np
import itertools
accuracy = np.trace(cm) / float(np.sum(cm))
misclass = 1 - accuracy
if cmap is None:
cmap = plt.get_cmap('Blues')
plt.figure(figsize=(8, 6))
plt.imshow(cm, interpolation='nearest', cmap=cmap)
plt.title(title)
plt.colorbar()
if target_names is not None:
tick_marks = np.arange(len(target_names))
plt.xticks(tick_marks, target_names, rotation=45)
plt.yticks(tick_marks, target_names)
if normalize:
cm = cm.astype('float') / cm.sum(axis=1)[:, np.newaxis]
thresh = cm.max() / 1.5 if normalize else cm.max() / 2
for i, j in itertools.product(range(cm.shape[0]), range(cm.shape[1])):
if normalize:
plt.text(j, i, "{:0.4f}".format(cm[i, j]),
horizontalalignment="center",
color="white" if cm[i, j] > thresh else "black")
else:
plt.text(j, i, "{:,}".format(cm[i, j]),
horizontalalignment="center",
color="white" if cm[i, j] > thresh else "black")
plt.tight_layout()
plt.ylabel('True label')
plt.xlabel('Predicted label\naccuracy={:0.4f}; misclass={:0.4f}'.format(accuracy, misclass))
plt.show()
答案 1 :(得分:0)
我在sklearn
的存储库中看到这仍是一个悬而未决的问题:
https://github.com/scikit-learn/scikit-learn/issues/3452
然而,有一些尝试实施它。来自相同的#3452线程问题:
您可以查看功能中建议的代码,看看是否符合您的需求。
答案 2 :(得分:0)
from sklearn.metrics import multilabel_confusion_matrix
mul_c = multilabel_confusion_matrix(
test_Y,
pred_k,
labels=["benign", "dos","probe","r2l","u2r"])
mul_c
答案 3 :(得分:0)
这对我来说最好:
from sklearn.metrics import multilabel_confusion_matrix
y_unique = y_test.unique()
mcm = multilabel_confusion_matrix(y_test, y_pred, labels = y_unique)
mcm
答案 4 :(得分:0)
我通过 sklearn 和 seaborn 库找到了一个简单的解决方案。
from sklearn.metrics import confusion_matrix, classification_report
from matplotlib import pyplot as plt
import seaborn as sns
def plot_confusion_matrix(y_test,y_scores, classNames):
y_test=np.argmax(y_test, axis=1)
y_scores=np.argmax(y_scores, axis=1)
classes = len(classNames)
cm = confusion_matrix(y_test, y_scores)
print("**** Confusion Matrix ****")
print(cm)
print("**** Classification Report ****")
print(classification_report(y_test, y_scores, target_names=classNames))
con = np.zeros((classes,classes))
for x in range(classes):
for y in range(classes):
con[x,y] = cm[x,y]/np.sum(cm[x,:])
plt.figure(figsize=(40,40))
sns.set(font_scale=3.0) # for label size
df = sns.heatmap(con, annot=True,fmt='.2', cmap='Blues',xticklabels= classNames , yticklabels= classNames)
df.figure.savefig("image2.png")
classNames = ['A', 'B', 'C', 'D', 'E']
plot_confusion_matrix(y_test,y_scores, classNames)
#y_test is your ground truth
#y_scores is your predicted probabilities