Question

我使用sed在目录中组合文本文件行。命令cd dir＆amp;＆amp; sed -e＆＃39; N; s / \ n //＆＃39; * .txt工作得很好，但是有没有办法可以调整它只合并以**开头的行句和以**结尾的后续句子。所以

This is Line1    
**This is Line2    
This is Line3**    
This is Line4    
This is Line5

变为

This is Line1    
** This is Line2 This is Line3**    
This is Line4    
This is Line5

等

Answer 1

您可以使用此sed：

sed '/^\*\*/{:loop; N; /\*\*$/{s/\n/ /g;p;d;}; b loop}' file

<强>测试

$ cat file
This is Line1
**This is Line2
in between
This is Line3**
This is Line4
**This is Line5
This is Line6**

$ sed '/^\*\*/{:loop; N; /\*\*$/{s/\n/ /g;p;d;}; b loop;}' file
This is Line1
**This is Line2 in between This is Line3**
This is Line4
**This is Line5 This is Line6**

Answer 2

Sed是你的朋友

$ sed '/^\*\*/{:l1;/\*\*$/!{N;bl1};s/\n/ /g;}' file
This is Line1

**This is Line2  This is Line3**

This is Line4

This is Line5

Answer 3

sed用于单个行上的简单替换，即全部。对于其他任何你应该使用awk。这将与您的示例输入/输出一起显示：

$ awk '{ORS=(/^\*\*/?FS:RS)}1' file
This is Line1
**This is Line2 This is Line3**
This is Line4
This is Line5

但当然它并没有解决您尚未与我们分享的任何要求（例如，当一行以**开头但下一行没有结束时该怎么做**或反之亦然或一行开头和结尾**或以**开头的行在输入文件的末尾或....）。

Answer 4

$ cat ip.txt
This is Line1
**This is Line2
This is Line3**
This is Line4
This is Line5 

$ # this slurps entire file
$ perl -0777 -pe 's/^(\*\*.*)\n(.*\*\*)$/$1 $2/mg' ip.txt 
This is Line1
**This is Line2 This is Line3**
This is Line4
This is Line5 

$ # can use this if testing start of line for ** is enough
$ perl -pe 's/\n/ / if /^\Q**/' ip.txt

参考：How do I search and replace across multiple lines with Perl?

Sed仅合并目录中的某些行

4 个答案: