我想为逗号分隔的字符串中的每个值运行我的存储过程。假设我有('10,20,30')所以sp应首先运行10然后运行20和30并将结果返回到单个表中。 Sp将为每个值返回单行。 我已经尝试使用游标,但没有像它应该的那样工作。
SET ANSI_NULLS OFF
GO
SET QUOTED_IDENTIFIER OFF
GO
ALTER PROCEDURE [dbo].[z_Formulas2]
(
@Fund_ID nvarchar, --('32,25,201')
@XFund_ID bigint,
@Start_Dated datetime,
@End_Dated datetime
)
AS
DECLARE @FUNDS TABLE(FundId BIGINT)
INSERT INTO @FUNDS
SELECT item FROM dbo.SplitString(@Fund_ID, ',') --Split string parse csv into table
SELECT * FROM @FUNDS
DECLARE @MyCursor CURSOR;
DECLARE @CurFund BIGINT;
BEGIN
SET @MyCursor = CURSOR FOR SELECT FundId FROM @FUNDS
OPEN @MyCursor
FETCH NEXT FROM @MyCursor
INTO @CurFund
WHILE EXISTS (SELECT FundId FROM @FUNDS)
BEGIN... --Logic part
FETCH NEXT FROM @MyCursor
INTO @CurFund
END
CLOSE @MyCursor ;
DEALLOCATE @MyCursor;
END
// dbo.SplitString
ALTER FUNCTION [dbo].[SplitString]
(
@Input NVARCHAR(MAX),
@Character CHAR(1)
)
RETURNS @Output TABLE (
Item NVARCHAR(1000)
)
AS
BEGIN
DECLARE @StartIndex INT, @EndIndex INT
SET @StartIndex = 1
IF SUBSTRING(@Input, LEN(@Input) - 1, LEN(@Input)) <> @Character
BEGIN
SET @Input = @Input + @Character
END
WHILE CHARINDEX(@Character, @Input) > 0
BEGIN
SET @EndIndex = CHARINDEX(@Character, @Input)
INSERT INTO @Output(Item)
SELECT SUBSTRING(@Input, @StartIndex, @EndIndex - 1)
SET @Input = SUBSTRING(@Input, @EndIndex + 1, LEN(@Input))
END
RETURN
END
答案 0 :(得分:1)
看起来没有正确使用光标。
DECLARE @MyCursor CURSOR;
DECLARE @CurFund BIGINT;
BEGIN
SET @MyCursor = CURSOR FOR SELECT FundId FROM @FUNDS
OPEN @MyCursor
FETCH NEXT FROM @MyCursor
INTO @CurFund
WHILE EXISTS (SELECT FundId FROM @FUNDS)
BEGIN
--Logic part
END
CLOSE @MyCursor ;
DEALLOCATE @MyCursor;
END
在此代码段中,跳过了FETCH NEXT
块中的另一个WHILE
运算符。使用WHILE @@FETCH_STATUS = 0
代替您的WHILE EXISTS (SELECT FundId FROM @FUNDS)
也是正确的,因为它始终会返回true
。