如何将逗号分隔的字符串拆分为存储过程中的字符串并将它们插入表字段?
使用Firebird 2.5
答案 0 :(得分:10)
这里有一个示例如何拆分字符串并将子字符串写入表中:
create procedure SPLIT_STRING (
AINPUT varchar(8192))
as
declare variable LASTPOS integer;
declare variable NEXTPOS integer;
declare variable TEMPSTR varchar(8192);
begin
AINPUT = :AINPUT || ',';
LASTPOS = 1;
NEXTPOS = position(',', :AINPUT, LASTPOS);
while (:NEXTPOS > 1) do
begin
TEMPSTR = substring(:AINPUT from :LASTPOS for :NEXTPOS - :LASTPOS);
insert into new_table("VALUE") values(:TEMPSTR);
LASTPOS = :NEXTPOS + 1;
NEXTPOS = position(',', :AINPUT, LASTPOS);
end
suspend;
end
答案 1 :(得分:10)
我发布修改后的迈克尔版本,也许对某人有用。
变化是:
set term ^ ;
create procedure split_string (
p_string varchar(32000),
p_splitter char(1) )
returns (
part varchar(32000)
)
as
declare variable lastpos integer;
declare variable nextpos integer;
begin
p_string = :p_string || :p_splitter;
lastpos = 1;
nextpos = position(:p_splitter, :p_string, lastpos);
if (lastpos = nextpos) then
begin
part = substring(:p_string from :lastpos for :nextpos - :lastpos);
suspend;
lastpos = :nextpos + 1;
nextpos = position(:p_splitter, :p_string, lastpos);
end
while (:nextpos > 1) do
begin
part = substring(:p_string from :lastpos for :nextpos - :lastpos);
lastpos = :nextpos + 1;
nextpos = position(:p_splitter, :p_string, lastpos);
suspend;
end
end^
set term ; ^
答案 2 :(得分:4)
使用 位置 http://www.firebirdsql.org/refdocs/langrefupd21-intfunc-position.html
和
SUSTRING http://www.firebirdsql.org/refdocs/langrefupd21-intfunc-substring.html
WHILE DO语句中的函数
答案 3 :(得分:3)
看起来不错,除了一件事,在我的Firebird服务器Varchar大小声明到32000导致“超出实现限制”异常所以要小心。我建议改用BLOB SUB_TYPE TEXT:)
答案 4 :(得分:2)
我使用的类似解决方案,前一段时间由Jiri Cincura发布 http://blog.cincura.net/232347-tokenize-string-in-sql-firebird-syntax/
recreate procedure Tokenize(input varchar(1024), token char(1))
returns (result varchar(255))
as
declare newpos int;
declare oldpos int;
begin
oldpos = 1;
newpos = 1;
while (1 = 1) do
begin
newpos = position(token, input, oldpos);
if (newpos > 0) then
begin
result = substring(input from oldpos for newpos - oldpos);
suspend;
oldpos = newpos + 1;
end
else if (oldpos - 1 < char_length(input)) then
begin
result = substring(input from oldpos);
suspend;
break;
end
else
begin
break;
end
end
end
答案 5 :(得分:1)
这在Informix数据库上对我有用:
DROP FUNCTION rrhh:fnc_StringList_To_Table;
CREATE FUNCTION rrhh:fnc_StringList_To_Table (pStringList varchar(250))
RETURNING INT as NUMERO;
/* A esta Funcion le podes pasar una cadena CSV con una lista de numeros
* Ejem: EXECUTE FUNCTION fnc_StringList_To_Table('1,2,3,4');
* y te devolvera una Tabla con dichos numeros separados uno x fila
* Autor: Jhollman Chacon @Cutcsa - 2019 */
DEFINE _STRING VARCHAR(255);
DEFINE _LEN INT;
DEFINE _POS INT;
DEFINE _START INT;
DEFINE _CHAR VARCHAR(1);
DEFINE _VAL INT;
LET _STRING = REPLACE(pStringList, ' ', '');
LET _START = 0;
LET _POS = 0;
LET _LEN = LENGTH(_STRING);
FOR _POS = _START TO _LEN
LET _CHAR = SUBSTRING(pStringList FROM _POS FOR 1);
IF _CHAR <> ',' THEN
LET _VAL = _CHAR::INT;
ELSE
LET _VAL = NULL;
END IF;
IF _VAL IS NOT NULL THEN
RETURN _VAL WITH RESUME;
END IF;
END FOR;
END FUNCTION;
EXECUTE FUNCTION fnc_StringList_To_Table('1,2,3,4');
SELECT * FROM TABLE (fnc_StringList_To_Table('1,2,3,4'));