在SQL SERVER中仅选择具有max(id)的行

时间:2016-08-12 07:57:38

标签: sql sql-server sql-server-2008

我有一张桌子A:

ID     | ProductCatId | ProductCode | Price
1      |       1      |  PROD0001   | 2
2      |       2      |  PROD0005   | 2
3      |       2      |  PROD0005   | 2
4      |       3      |  PROD0008   | 2
5      |       5      |  PROD0009   | 2
6      |       7      |  PROD0012   | 2

我想选择ID,ProductCatId,ProductCode,Price with condition: “如果ProductCatId存在相同的值,那么请使用max(ID)”获取ProductCatId,如:

ID     | ProductCatId | ProductCode | Price
1      |       1      |  PROD0001   | 2
3      |       2      |  PROD0005   | 2
4      |       3      |  PROD0008   | 2
5      |       5      |  PROD0009   | 2
6      |       7      |  PROD0012   | 2

4 个答案:

答案 0 :(得分:3)

转到窗口函数和row_number()

select ID , ProductCatId , ProductCode , Price
  from (
        select ID , ProductCatId , ProductCode , Price, row_number() over (partition by ProductCatId order by ID desc) as rn
         from myTable
        ) as t
  where t.rn = 1

答案 1 :(得分:2)

你可以试试这个,

Select Max(ID),ProductCatId,ProductCode,price
From TableName
Group By ProductCatId,ProductCode,price

答案 2 :(得分:1)

select 
top 1 with ties
ID,ProductCatId,ProductCode,Price
from
table
order by
row_number() over (partition by productcatid order by id desc)

答案 3 :(得分:1)

可以使用row_number()

select t.*
from (select t.*,
             row_number() over (partition by ProductCatId order by ID desc) as seqnum
      from @Table t
     ) t
where seqnum = 1
order by ID;