Question

我试图将一个将你的名字改成数字的东西编码，而且我不确定我是不是最简单甚至最直接的方式。我对编程很陌生。

public class Project1 {

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
    // TODO code application logic here
    char ch1 = 'a';
    char ch2 = 'b';
    char ch3 = 'c';
    char ch4 = 'd';
    char ch5 = 'e';
    char ch6 = 'f';
    char ch7 = 'g';
    char ch8 = 'h';
    char ch9 = 'i';
    char ch10 = 'j';
    char ch11 = 'k';
    char ch12 = 'l';
    char ch13 = 'm';
    char ch14 = 'n';
    char ch15 = 'o';
    char ch16 = 'p';
    char ch17 = 'q';
    char ch18 = 'r';
    char ch19 = 's';
    char ch20 = 't';
    char ch21 = 'u';
    char ch22 = 'v';
    char ch23 = 'w';
    char ch24 = 'x';
    char ch25 = 'y';
    char ch26 = 'z';

    int num1 = ch1 - 'a' + 1;
    int num2 = ch2 - 'a' + 1;
    int num3 = ch3 - 'a' + 1;
    int num4 = ch4 - 'a' + 1;
    int num5 = ch5 - 'a' + 1;
    int num6 = ch6 - 'a' + 1;
    int num7 = ch7 - 'a' + 1;
    int num8 = ch8 - 'a' + 1;
    int num9 = ch9 - 'a' + 1;
    int num10 = ch10 - 'a' + 1;
    int num11 = ch11 - 'a' + 1;
    int num12 = ch12 - 'a' + 1;
    int num13 = ch13 - 'a' + 1;
    int num14 = ch14 - 'a' + 1;
    int num15 = ch15 - 'a' + 1;
    int num16 = ch16 - 'a' + 1;
    int num17 = ch17 - 'a' + 1;
    int num18 = ch18 - 'a' + 1;
    int num19 = ch19 - 'a' + 1;
    int num20 = ch20 - 'a' + 1;
    int num21 = ch21 - 'a' + 1;
    int num22 = ch22 - 'a' + 1;
    int num23 = ch23 - 'a' + 1;
    int num24 = ch24 - 'a' + 1;
    int num25 = ch25 - 'a' + 1;
    int num26 = ch26 - 'a' + 1;



    String name = JOptionPane.showInputDialog(null,"Enter your name:");

    System.out.println("your name is: " +name);
}
}

Answer 1

试试这个

String name = "abc";
char[] chars = name.toCharArray();
for (char c : chars) {
    System.out.print(c-'a'+1);
}

Answer 2

您可以更轻松地完成此任务。

由于您没有说如何将字符串转换为数字/数字。我会给你一些选择。

首先，您可以使用hashCode。此方法为每个唯一字符串返回唯一值：

String name = JOptionPane.showInputDialog(null,"Enter your name:");

System.out.println("your name is: " + name.hashCode());

所以，如果我进入＆＃34; Sweeper＆＃34;和＆＃34; Sweeper＆＃34;，输出将是相同的：

your name is: -143341447

或者，您可以将char转换为int，将每个字符转换为相应的ASCII代码：

String name = JOptionPane.showInputDialog(null,"Enter your name:");
char[] chars = name.toCharArray();
System.out.print("your name is: ");
for (char c : chars) {
    System.out.print((int)c);
    System.out.print(" ");
}

进入＆＃34;清扫工＆＃34;将输出：

your name is: 83 119 101 101 112 101 114

另一种方法是添加ASCII值：

String name = JOptionPane.showInputDialog(null,"Enter your name:");
char[] chars = name.toCharArray();
System.out.print("your name is: ");
int sum = 0;
for (char c : chars) {
    sum += (int)c;
}
System.out.println(sum);

＆＃34;清扫＆＃34;输入将产生：

your name is: 731

您还可以在HashMap<Character, Integer>中添加a-z和A-Z，为每个角色提供自定义值：

HashMap<Character, Integer> map = new HashMap<>();
map.put('a', 1);
map.put('b', 2);
map.put('c', 3);
map.put('d', 4);
map.put('e', 5);
// and so on...

String name = JOptionPane.showInputDialog(null,"Enter your name:");
char[] chars = name.toCharArray();
System.out.print("your name is: ");
for (char c : chars) {
    System.out.print(map.get(c));
    System.out.print(" ");
}

我试图将名称输入转换为数字

2 个答案: